The first trna's anticodon loop, which will complement this mrna, is 3' GGC 5'.
<h3>What is anticodon ?</h3>
A complementary codon in messenger RNA binds to a triplet of nucleotide bases in transfer RNA that identifies the amino acid delivered during protein synthesis at a ribosome.
A codon is a trio of nucleotides, or triplet, that can be found on mRNA and codes for a certain amino acid when it is translated. A bond is created when an anticodon, which is a three-nucleotide sequence on tRNA, meets with the matching sequence on mRNA.
Each tRNA has a trio of bases known as an anti-codon. to determine the entire anti-codon sequence required to match a certain strand of mRNA. to match the complementary nucleotides in the mRNA sequence.
To learn more about anticodon from the given link:
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Answer:
56.24g
Explanation:
To find the mass of N2O3 in 4.45 x 10^23 molecules, it must first be converted to moles by dividing the number of molecules in N2O3 by Avagadro's number (6.02 × 10^23).
number of moles in N2O3 = 4.45 x 10^23 ÷ 6.02 × 10^23
n = 4.45/6.02 × 10^(23 - 23)
n = 0.74 × 10^0
n = 0.74moles.
Using the formula below to find the mass of N2O3;
mole = mass ÷ molar mass
Molar mass of N2O3 = 14(2) + 16(3)
= 28 + 48
= 76g/mol
mass = mole × molar mass
Mass = 0.74 × 76
Mass = 56.24g
Answer:
Positively Charged
Explanation:
The is a group XVI and period 4 element of the periodic table with similar physical and chemical to that of tellurium and sulfur. Selenium exist in different allotropic forms, which have different solubility including selenate, selenite and selenium in elemental form
The Se ion in selenate has a positive charge of +6, while the selenate ion has a charge of -2
The Se ion in selenite has a charge of +4, while the selenite ion has a negative charge of -2.
The charge of Se in elemental selenium is 0.
Answer:
M = 0.441 M
Explanation:
In this case, we have two solutions that involves the Manganese II cation;
We have Mn(CH₃COOH)₂ and MnSO₄
In both cases, the moles of Mn are the same in reaction as we can see here:
Mn(CH₃COO)₂ <-------> Mn²⁺ + 2CH₃COO⁻
MnSO₄ <------> Mn²⁺ + SO₄²⁻
Therefore, all we have to do is calculate the moles of Mn in both solutions, do the sum and then, calculate the concentration with the new volume:
moles of MnAce = 0.489 * 0.0283 = 0.0138 moles
moles MnSulf = 0.339 * 0.0125 = 0.0042 moles
the total moles are:
moles of Mn²⁺ = 0.0138 + 0.0042 = 0.018 moles
Finally the concentration: 12.5 + 28.3 = 40.8 mL or 0.0408 L
M = 0.018 / 0.0408
M = 0.441 M
This would be the final concentration of the manganese after the mixing of the two solutions
Answer:
Well, Aluminum Oxide has a very high melting point. Carbon dioxide has a very low boiling point.
Explanation:
They are both talking about different things, melting and boiling. Aluminum Oxide's melting point is much higher then carbon dioxide's melting point. Hope this help, and good luck on your assignment (if one)
