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gladu [14]
3 years ago
9

Over coffee and croissants at breakfast one day, your friend Eissa (an expert chemist) says this:

Chemistry
1 answer:
slega [8]3 years ago
4 0

Answer:

I have the same question

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If their is a question with the anwser “both ___” it’s that

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Prevent the release of toxic vapored, dusts, mists, or gases into the workplace air
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ACTUAL YIELD VS THEORETICAL YIELD?
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Actual yield over theoretical yield, then multiply by 100

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The metal content of iron in ores can be determined by a redox procedure in which the sample is first oxidized with Br2 to conve
coldgirl [10]

Answer:

80.27%

Explanation:

Let's consider the following balanced equation.

2 Fe³⁺(aq) + Sn²⁺(aq) ⇒ 2Fe²⁺(aq) + Sn⁴⁺(aq)

First, we have to calculate the moles of Sn²⁺ that react.

\frac{0.1015molSn^{2+} }{1L} .13.28 \times 10^{-3} L=1.348\times 10^{-3}molSn^{2+}

We also know the following relations:

  • According to the balanced equation, 1 mole of Sn²⁺ reacts with 2 moles of Fe³⁺.
  • 1 mole of Fe³⁺ is oxidized from 1 mole of Fe.
  • The molar mass of Fe is 55.84 g/mol.

Then, for 1.348 × 10⁻3 moles of Sn²⁺:

1.348\times 10^{-3}molSn^{2+}.\frac{2molFe^{3+} }{1molSn^{2+} } .\frac{1molFe}{1molFe^{3+} } .\frac{55.84gFe}{1molFe} =0.1505gFe

If there are 0.1505 g of Fe in a 0.1875 g sample, the mass percentage of Fe is:

\frac{0.1505g}{0.1875g} \times 100 \% = 80.27\%

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3 years ago
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44.0095 you're welcome hope this helps

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3 years ago
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