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4 years ago

12

Shiloh wanted to observe the changes that occurred during an exothermic reaction. He monitored the changes and placed them in a

chart.

1 answer:

Nostrana [21]4 years ago

7 0

<span>The activation energy was reached was 10:45 a.m. The additional energy did not affect the reaction.</span>

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How might a titration be different if<br> a.1m base solution that produces 2 moles of hydroxide g?

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Use higher concentration of acid to produce 2 moles of hydrogen to form water

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3 years ago

What is the molarity of a solution that has 2.87 moles of NaCl in 5020 mL of solution?

Umnica [9.8K]

2.87 mol/5.020 L (converting mL to L) = .572M

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3 years ago

Define the clinical thermometer

Sloan [31]

Answer:

a small medical thermometer with a short but finely calibrated range, for taking a person's temperature.

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3 years ago

Read 2 more answers

A small bubble rises from the bottom of a lake where the temperature and pressure are 4.0 C and 3.0 atm, to the water’s surface,

Varvara68 [4.7K]

Answer:

The final volume of the bubble is 7.13 mL.

Explanation:

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 3 atm

$P_2$ = final pressure of gas = 0.95 atm

$V_1$ = initial volume of gas = $2.1 mL=0.0021 L$

$V_2$ = final volume of gas = ?

$T_1$ = initial temperature of gas = $4^oC=273.15+4K=277.15 K$

$T_2$ = final temperature of gas = $25^oC=273.15+25 k=298 .15 K$

Now put all the given values in the above equation, we get:

$\frac{3 atm\times 0.0021 L}{277.15 K}=\frac{0.95 atm\times V_2}{298.15 K}$

$V_2=\frac{3 atm\times 0.0021 L\times 298.15 K}{277.15 K\times 0.95 atm}=0.00713 L = 7.13 mL$

The final volume of the bubble is 7.13 mL.

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3 years ago

Thymine is always joined to

WARRIOR [948]

Adenine.

Thymine always pairs with Adenine while Cytosine always pairs with Guanine on DNA strands.

Hope this helps!

4 0

4 years ago