Answer:
second-law efficiency = 62.42 %
Explanation:
given data
temperature T1 = 1200°C = 1473 K
temperature T2 = 20°C = 293 K
thermal efficiency η = 50 percent
solution
as we know that thermal efficiency of reversible heat engine between same temp reservoir
so here
efficiency ( reversible ) η1 = 1 -
............1
efficiency ( reversible ) η1 = 1 -
so efficiency ( reversible ) η1 = 0.801
so here second-law efficiency of this power plant is
second-law efficiency =
second-law efficiency =
second-law efficiency = 62.42 %
Explanation:
Conservation of velocity equation
Answer:
Heat flux of CO₂ in cgs
= 170.86 x 10⁻⁹ mol / cm²s
SI units
170.86 x 10⁻⁸ kmol/m²s
Explanation:
Answer:
I forget the word for it, but probably the guys who set up the power lines in the city.
Explanation: