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AfilCa [17]
1 year ago
10

(a) What is the charge density of an ion, and what two properties of an ion affect it?

Chemistry
1 answer:
olga nikolaevna [1]1 year ago
6 0

Charge density is the ratio of the charge of ions to the volume of ions.

<h3> Factor affecting charge density</h3>

It depends on the following properties of ion as

  • Charge on the ion.
  • Volume of the ions.

The lithium ion, Li⁺, has half of the radius of the potassium ion, K⁺. That is why, Li⁺ have a electric field 4 times stronger than the electric field of K⁺ and thus it have 4 times stronger force of attraction.

All the ions: Li⁺, Na⁺, K⁺, Rb⁺, Cs⁺, have the similar electric charge +1.6×10⁻¹⁹ C. As we know that, volume is directly proportional to the third power of their radius. Therefore, smaller ions have less charge density than bigger one.

We can say that charge density decreases down across period due to decrease in the radius which further reduces the volume of ions.

Charge density increases along group due to increase in the radius which further increases the volume of ions.

Thus, we can say that charge density depends on the charge and volume of the ions.

learn more about charge density:

brainly.com/question/15810178

#SPJ4

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Suppose that you add 26.7 g of an unknown molecular compound to 0.250 kg of benzene, which has a K f Kf of 5.12 oC/m. With the a
kiruha [24]

From the calculation, the molar mass of the solution is 141 g/mol.

<h3>What is the molar mass?</h3>

We know that;

ΔT = K m i

K = the freezing constant

m = molality of the solution

i = the Van't Hoft factor

The molality of the solution is obtained from;

m = ΔT/K i

m = 3.89/5.12 * 1

m = 0.76 m

Now;

0.76 =  26.7 /MM/0.250

0.76 = 26.7 /0.250MM

0.76 * 0.250MM =  26.7

MM= 26.7/0.76 * 0.250

MM = 141 g/mol

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5 0
2 years ago
When the following equation is balanced using the smallest possible integers, what is the number in front of the substance in bo
weeeeeb [17]

The balanced equation :

8Al + 3Fe₃O₄→ 4Al₂O₃ + 9Fe

You just have to look for which element is in bold because the question is not clear

<h3>Further explanation</h3>

Equalization of chemical reaction equations can be done using variables. Steps in equalizing the reaction equation:

1. gives a coefficient on substances involved in the equation of reaction such as a, b, or c etc.

2. make an equation based on the similarity of the number of atoms where the number of atoms = coefficient × index between reactant and product

3. Select the coefficient of the substance with the most complex chemical formula equal to 1

Reaction

Al + Fe₃O₄→ Al₂O₃ + Fe

give a coefficient

aAl + Fe₃O₄→ bAl₂O₃ + cFe

O, left=4, right=3b⇒3b=4⇒b=4/3

Al, left=a, right=2b⇒a=2b⇒a=2.4/3⇒a=8/3

Fe, left=3, right=c⇒c=3

The equation becomes :

8/3Al + Fe₃O₄→ 4/3Al₂O₃ + 3Fe x3

8Al + 3Fe₃O₄→ 4Al₂O₃ + 9Fe

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