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krek1111 [17]
2 years ago
9

ox A has a mass of 20.0kg and Box B has a mass of 30.0kg. Box A is placed on a horizontal surface that is frictionless and Box B

is hanging from a pulley by a rope connected to Box A. If the acceleration of the system is 5.88m/s2, what is the Tension T on Box A?
Physics
1 answer:
MatroZZZ [7]2 years ago
3 0

The tension on box A is 117.6 N

<h3 /><h3>What is Equilibrium of Forces ?</h3>

Equilibrium is a state of an object with respect to a given observable quantity during the time for which there is no change in that quantity.

A body is said to be in equilibrium when:

  • the body as a whole either remains at rest or moves in a straight line with constant speed.
  • the body is either not rotating at all or is rotating at a constant angular velocity.

Given that box A has a mass of 20.0kg and Box B has a mass of 30.0kg. Box A is placed on a horizontal surface that is frictionless and Box B is hanging from a pulley by a rope connected to Box A.

The tension in the rope will be the same.

Given that Box A is placed on a horizontal surface that is frictionless, that is,

T = ma .... (1)

Also,  Box B is hanging from a pulley by a rope connected to Box A. That is,

W - T = ma ...... (2)

Where W = mg

Since the acceleration of the system is 5.88m/s² which will be the same for the two equations, then the Tension T on Box A can be calculated by substituting acceleration and mass into equation (1)

T = 20 x 5.88

T = 117.6 N

Therefore, the tension on box A is 117.6 N

Learn more about Equilibrium of Forces here: brainly.com/question/517289

#SPJ1

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3 years ago
A 1.50-V battery supplies 0.414 W of power to a small flashlight. If the battery moves 4.93 1020 electrons between its terminals
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2.86×10⁻¹⁸ seconds

Explanation:

Applying,

P = VI................ Equation 1

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make I the subject of the equation

I = P/V................ Equation 2

From the question,

Given: P = 0.414 W, V = 1.50 V

Substitute into equation 2

I = 0.414/1.50

I = 0.276 A

Also,

Q = It............... Equation 3

Where Q = amount of charge, t = time

make t the subject of the equation

t = Q/I.................. Equation 4

From the question,

4.931020 electrons has a charge of (4.931020×1.6020×10⁻¹⁹) coulombs

Q = 7.899×10⁻¹⁹ C

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t =  7.899×10⁻¹⁹/0.276

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A 1.5 kg ball pushed with a force of 13.5 N accelerates to the left. What is the acceleration of the ball?​
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Answer : The final pressure in the two containers is, 2.62 atm

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Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

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Thus, the expression for final pressure in the two containers will be:

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V_2 = volume of Ar gas = 2.00 L

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Now put all the given values in the above equation, we get:

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