Answer:
Depending on the deformity it will depend on the amount of the ice that is melted,it the majority is melted that is relevant to the heated liquid melting the ice,so yes only the water formalities of the melted ice.
Answer:
a. polar solutes dissolve in polar solvents.
Explanation:
Polarity is a phenomenon that has to do with the positive and negative electric (ionic) charges of a molecule. A molecule with distinct positive and electric charge is said to be POLAR. However, water is said to be a universal solvent because it dissolves more substances than any other solvent can.
This solvent property of water is a function of its POLARITY. Polar solutes dissolve in polar solvents. Hence, only polar solutes can dissolve in water (a polar solvent). Hence, in this case, CH3OCH3 (ether) will dissolve in water because it is a POLAR molecule/solute.
Answer:
ΔH =
Explanation:
In a calorimeter, when there is a complete combustion within the calorimeter, the heat given off in the combustion is used to raise the thermal energy of the water and the calorimeter.
The heat transfer is represented by
=
where
= the internal heat gained by the whole calorimeter mass system, which is the water, as well as the calorimeter itself.
= the heat of combustion
Also, we know that the total heat change of the any system is
ΔH = ΔQ + ΔW
where
ΔH = the total heat absorbed by the system
ΔQ = the internal heat absorbed by the system which in this case is
ΔW = work done on the system due to a change in volume. Since the volume of the calorimeter system does not change, then ΔW = 0
substituting into the heat change equation
ΔH = + 0
==> ΔH =
Answer:
First, precipitate of AgCl is formed. Second, a soluble complex of silver and ammonia is formed. Third, AgCl is reproduced due to disappearance of ammonia complex in presence of .
Explanation:
In presence of NaCl, forms an insoluble precipitate of AgCl.
Reaction:
In presence of , AgCl gets dissolved into solution due to formation of soluble complex.
Reaction:
In presence of , complex gets destroyed and free again reacts with free to produce insoluble AgCl
Reaction:
I think the answer is solvent but i'm not very sure.