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Snowcat [4.5K]
2 years ago
6

A gram of fat stores _____ energy than a gram of starch due to ______ within fat molecules relative to starch molecules.

Chemistry
1 answer:
Gwar [14]2 years ago
7 0

A gram of fat stores more energy than a gram of starch due to more C-H bonds  within fat molecules relative to starch molecules.

The energy released/stored by nutrients is known as calorific value.

The calorific value of a  substance is expressed in kilo calories(kcal).

1 kcal is defined the amount of energy required to raise the temperature of 1 kg of water by 1 °C.

The physiological calorific value of fats and carbohydrates is 9.0 kcal/g and 4.0 kcal/g respectively.

As it is evident from these values that the energy stored per gram of fat is more than the energy stored per gram of starch.

Now, the reason behind this difference in energies between these two molecules is due to the different number of C-H bonds present in them, as is evident from the adjoining images.

Therefore, A gram of fat stores more energy than a gram of starch due to more C-H bonds within fat molecules relative to starch molecules.

To know more about "calorific values", refer to the following link:

brainly.com/question/14600638?referrer=searchResults

#SPJ4

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The density of seawater is 1.025 g/ml what is the mass of 100,000 ml of seawater in grams
melamori03 [73]
D = m / V

1.025 = m / 100,000 mL

m = 1.025 x 100,000

m = 102,500 g
8 0
3 years ago
How many moles of CF4 could be made from 456g of F?
lord [1]

Answer:

132 moles dhhdhsysushdgdgsgsgsgsgsv

3 0
2 years ago
Consider the reaction of peroxydisulfate ion (S2O2−8) with iodide ion (I−) in aqueous solution: S2O2−8(aq)+3I−(aq)→2SO2−4(aq)+I−
kolbaska11 [484]

Answer:

r = 3.61x10^{-6} M/s

Explanation:

The rate of disappearance (r) is given by the multiplication of the concentrations of the reagents, each one raised of the coefficient of the reaction.

r = k.[S2O2^{-8} ]^{x} x [I^{-} ]^{y}

K is the constant of the reaction, and doesn't depends on the concentrations. First, let's find the coefficients x and y. Let's use the first and the second experiments, and lets divide 1º by 2º :

\frac{r1}{r2} = \frac{0.018^{x} x0.036^{y} }{0.027^xx0.036^y}

\frac{2.6x10^{-6}}{3.9x10^{-6}} = (\frac{0.018}{0.027})^xx(\frac{0.036}{0.036})^y

0.67 = 0.67^x

x = 1

Now, to find the coefficient y let's do the same for the experiments 1 and 3:

\frac{r1}{r3} = \frac{0.018x0.036^y}{0.036x0.054^y}

\frac{2.6x10^{-6}}{7.8x10^{-6}} = (\frac{0.018}{0.036})x(\frac{0.036}{0.054})^y

0.33 = 0.5x 0.67^y

0.67 = 0.67^y

y = 1

Now, we need to calculate the constant k in whatever experiment. Using the first :

2.6x10^{-6} = kx0.018x0.036kx6.48x10^{-4} = 2.6x10^{-6}

k = 4.01x10^{-3} M^{-1}s^{-1}[/tex]

Using the data given,

r = 4.01x10^{-3}x1.8x10^{-2}x5.0x10^{-2}

r = 3.61x10^{-6} M/s

7 0
3 years ago
Assume a gasoline is isooctane, which has a density of 0.692 g/ml. What is the mass of 3.8 gal of the gasoline (1 gal = 3.78 l)?
sveticcg [70]

Density is the ratio of mass to the volume.

The mathematical expression is given as:

density=\frac{mass}{volume}

Now, density of isooctane = 0.692 g/mL

Volume  = 3.8 gal

Since, 1 gallon = 3.78 L

So, 3.8 gal = 3.78 L\times 3.8

= 14.364 L

As, 1 L = 1000 mL

Therefore, 14.364 L= 14.364 L\times 1000 mL

Volume in mL = 14364 mL

Put the values,

0.692 g/mL=\frac{mass}{14364 mL}

m = 0.692 g/mL\times 14364 mL

= 9939.888 g

Hence, mass of 3.8 gal of the gasoline is 9939.888 g.



6 0
3 years ago
Please help with this question ;/
aev [14]
The link above is a hacker
8 0
3 years ago
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