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balu736 [363]
1 year ago
5

2. Why is it important in gravimetric analysis to add an excess amount of precipitating ions to a solution containing an analyte

? ​
Chemistry
1 answer:
Wewaii [24]1 year ago
8 0

It is important in gravimetric analysis to add an excess amount of precipitating ions to a solution containing an analyte because it helps to determine the mass of the analyte.

<h3>What is Gravimetric analysis?</h3>

This is a method which is used in the determination of the quantitative determination of the ion being analyzed(analyte) based on its mass.

Adding an excess amount of precipitating ions to a solution containing an analyte will make it easier for the mass of an analyte to be determined.

It is also important for the precipitate to be a pure substance with a definite and known composition which therefore makes it the most appropriate reason.

Read more about Gravimetric analysis here brainly.com/question/6163057

#SPJ1

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yawa3891 [41]
I think this is what you wanted, so good luck!

8 0
3 years ago
What temperature would 3.54 moles of xenon gas need to reach to exert a pressure of 1.57 atm at a volume of 34.6 l
ira [324]

Answer:

186.9Kelvin

Explanation:

The ideal gas law equation is PV = n R T

where

P   is the pressure of the gas

V   is the volume it occupies

n  is the number of moles of gas present in the sample

R  is the universal gas constant, equal to  0.0821 atm L /mol K

T  is the absolute temperature of the gas

Ensure units of the volume, pressure, and temperature of the gas correspond to R ( the universal gas constant, equal to  0.0821 atm L /mol K )

n = 3.54moles

P= 1.57

V= 34.6

T=?

PV = n R T

PV/nR = T

1.57 x 34.6/3.54 x 0.0821

54.322/0.290634= 186.908620464= T

186.9Kelvin ( approximately to 1 decimal place)

5 0
3 years ago
B. Which of the following compounds can
Tamiku [17]

Answer:

The correct answer is:

d. Na2S, NaF

4 0
3 years ago
Read 2 more answers
Please answer asap need it by Wednesday morning
marta [7]

Answer:

1.7 PH

Explanation:

Ph= -log(0.02)= 1.698

6 0
3 years ago
What is the coefficient for hydrogen in the balanced equation for the reaction of solid molybdenum(iv) oxide with gaseous hydrog
anastassius [24]

The  coefficient  for hydrogen  in  the  balanced  equation   of solid  molybdenum(iV)  oxide  with gaseous  hydrogen  is  2


 Explanation

Coefficient   is defined  to  as  a number  in front   of a chemical formula in a  balanced chemical equation.

   The  reaction   of   molybdenum (iv) oxide  with  gaseous  hydrogen  is  as below,


MoO2  + 2 H2→  Mo  +2 H2O

From   balanced equation above  the coefficient   for  H2  is  2  since  the number in  front of  H2  is 2



3 0
3 years ago
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