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balu736 [363]
1 year ago
5

2. Why is it important in gravimetric analysis to add an excess amount of precipitating ions to a solution containing an analyte

? ​
Chemistry
1 answer:
Wewaii [24]1 year ago
8 0

It is important in gravimetric analysis to add an excess amount of precipitating ions to a solution containing an analyte because it helps to determine the mass of the analyte.

<h3>What is Gravimetric analysis?</h3>

This is a method which is used in the determination of the quantitative determination of the ion being analyzed(analyte) based on its mass.

Adding an excess amount of precipitating ions to a solution containing an analyte will make it easier for the mass of an analyte to be determined.

It is also important for the precipitate to be a pure substance with a definite and known composition which therefore makes it the most appropriate reason.

Read more about Gravimetric analysis here brainly.com/question/6163057

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Which of the following is the best name for a compound made from calcium and bromine? (CaBr2) calcium bromide calcium dibromide
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Calcium bromide

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When naming compounds, the use of prefixes depend on the type of bond made. In this case, calcium and bromine form a ionic bond because calcium is a metal and bromine is a non-metal.

Ionic bonds are not named using prefixes. So no matter how many atoms there are, you will simply write the name of the element for the first element.

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7 0
3 years ago
What is the molecular formula for a compound that is 44.87% potassium, 36.7%
Phoenix [80]

Answer:

Molecular formula: S4K8O16  empirical formula: SK2O4

Explanation:

First we find the moles of each by first finding grams (using the percent) and then using stoichiometry to convert into moles:

Sulfur: 696 *.18 = 125.28grams S* \frac{1 mole S}{32.065 g S} = 3.907 moles S

Potassium: 696 *.4487 = 312.2952 *\frac{1 mole K}{39.08 g K}= 7.99117 mole K

Oxygen: 696 * .367 = 255.432 * \frac{1 mol O}{16g O} = 15.9654 mole O

Then we divide each value by the atom with the smallest number of moles to find the mole ratio:

3.907/3.907= 1

7.99117 mole K/ 3.907= 2.043

15.9654 mole O/ 3.907= 4.08

The empirical formula is SK2O4

To find the molecular formula, we divide the mass given (696) by the mass of the empirical formula (174.22) to get 4. We then divide each atom by 4.

Molecular formula: S4K8O16

5 0
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