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SVETLANKA909090 [29]
2 years ago
9

A train slows down as it pulls into a station. if the train is moving from your left to your right, what are the directions of t

he vectors for velocity and acceleration?
Physics
1 answer:
navik [9.2K]2 years ago
3 0

The directions of the vectors for velocity and acceleration are in the opposite directions.

  • The velocity vector is always in the direction of motion of the object. So, the direction of velocity is in the right from our point of view.
  • When there is a positive acceleration in the object the acceleration vector is in the direction of motion of the object. When there is a negative acceleration in the object the acceleration vector is in the opposite direction of motion of the object. So, the direction of velocity is in the left from our point of view.

Velocity vector is the rate of change of position of an object. Acceleration vector is the rate of change of velocity of an object.

Therefore, the directions of the vectors for velocity and acceleration are in the opposite directions.

To know more about velocity and acceleration vectors

brainly.com/question/13492374

#SPJ4

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Help me please!!!!!!!!!!!!!/ Science
Elan Coil [88]
I don't understand that I'm sorry what grade is that
5 0
3 years ago
Consider the uniform electric field E = (8.0ĵ + 2.0 ) ✕ 103 N/C. What is its electric flux (in N · m2/C) through a circular area
cluponka [151]

Answer:

5.09 x 10⁵ Nm²/C

Explanation:

The electric flux φ through a planar area is defined as the electric field Ε times the component of the area Α perpendicular to the field. i.e

φ = E A

From the question;

E = (8.0j + 2.0k) ✕ 10³ N/C

r = radius of the circular area = 9.0m

A = area of a circle = π r²           [Take π = 3.142]

A = 3.142 x 9² = 254.502m²

Now, since the area lies in the x-y plane, only the z-component of the electric field is responsible for the electric flux through the circular area.

Therefore;

φ = (2.0) x 10³ x 254.502

φ = 5.09 x 10⁵ Nm²/C

The electric flux is 5.09 x 10⁵ Nm²/C

4 0
3 years ago
You are travelling by skateboard at 3.0 m/s and start to accelerate. If you
vovangra [49]

Answer: 8m/s

Explanation:

Vs= 3 m/s

Vf=?

a=0.5m/s²

t=10s

-----------

a=Vf-Vs/t

at=Vf-Vs

0.5*10s=Vf-Vs

5m/s=Vf-3m/s

5m/s+3m/s=Vf

Vf=8m/s

6 0
3 years ago
a rod of zinc has a mass of 5kg. in water it weighs 25 N. what is the buoyant force on it when it is submerged in water?
Alexxandr [17]

Answer:

If it has a mass of 5 kg its weight is 5 kg * 9.8 m/s^2 = 49 N

Weight in air = 49 N

Weight in water = 25 N

Buoyant force provided by water = 49 - 25 = 24 N

7 0
3 years ago
A 600-kg car traveling at 30.0 m/s is going around a curve having a radius of 120 m that is banked at an angle of 25.0°. The coe
ikadub [295]

Answer:

f_{fr}=1590.85 N

Explanation:

Here the total force at the horizontal components will be equal to the centripetal force on the car. So we will have:

f_{fr}cos(25)+Nsin(25)=m\frac{v^{2}}{r} (1)

  • f(fr) is the friction force
  • N is the normal force

Now, the sum of forces at the vertical direction is equal to 0.

Ncos(25)-mg-f_{fr}sin(25)=0 (2)          

Let's combine (1) and (2) to find f(fr)

f_{fr}=\frac{(mv^{2}/r)-mgtan(25)}{cos(25)+tan(25)sin(25)}

f_{fr}=\frac{(600*30^{2}/120)-600*9.81*tan(25)}{cos(25)+tan(25)sin(25)}  

f_{fr}=1590.85 N

I hope it helps you!

5 0
3 years ago
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