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OleMash [197]
3 years ago
11

Two identical satellites orbit the earth in stable orbits. Onesatellite orbits with a speed vat a distance rfrom the center of t

he earth. The second satellite travels at aspeed that is less than v.At what distance from the center of the earth does the secondsatellite orbit?
a) At a distance that is less than r.
b) At a distance equal to r.
c) At a distance greater than r.
Physics
1 answer:
Lelu [443]3 years ago
5 0

Answer:

c) At a distance greater than r

Explanation:

If G= Gravitational constant

M= Mass of earth

r= distance from earth center

then orbital speed is ;

v = \sqrt{\frac{GM}{r} }

==> v²=GM/r

If speed of first satellite = V₁

==> V₁² = GM/r

==> r = GM/V₁²

If speed of second satellite say V₂ is less than V₁ then square of V₂ will be less than square of V₁ , and hence GM will be divided by less number in case of second satellite, and hence will give greater value of r as compared to first satellite.

So our answer is c

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Yes, if we know the Earth's mass

Explanation:

The momentum of an object is a vector quantity given by the equation

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m is the mass of the object

v is its velocity

In this case, we are asked if we can find the velocity of the Earth by starting from its momentum. Indeed, we can. In fact, we can rewrite the equation above as

v=\frac{p}{m}

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3 years ago
How many grams of CO2 are in 10 mol of the compound?
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For our problem, this means that one mole of CO2 has a mass of 44.01 grams. So 22 grams divided by 44.01 grams is roughly 0.5 moles of CO2.


hope it helps

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3 years ago
Photons with the highest energy have the longest period
xz_007 [3.2K]

FALSE this is not true

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8 0
3 years ago
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What school did Ronald McNair go to and what kind of science did he work in
alina1380 [7]

Answer:

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5 0
3 years ago
An uncharged capacitor is connected to the terminals of a 4.0 V battery, and 6.0 μC flows to the positive plate. The 4.0 V batte
Ugo [173]

Answer:

1 μC extra charge will be flow here

Explanation:

Given data

battery V1 = 4.0 V

flows Q1 =  6.0 μC

replace battery V2 = 7.0 V

to find out

what happen if we replace battery

solution

we apply here principal of capacitor

that is Q directly proportional voltage

so we say Q2/Q1 = V2/ V1

put all value here

Q2/Q1 = V2/ V1

Q2/6 = 7/ 6

Q2 = 7

so we see here 7 μC will be flow

and Q = Q2 - Q1 = 7 - 6 = 1 μC

so we also say that 1 μC extra charge will be flow here

5 0
3 years ago
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