The distance the object willl fall durring the 2nd seconds is 4.9 m
<h3>Data obtained from the question</h3>
The following data were obtained from the question:
- Initial velocity (u) = 0 m/s
- Acceleration due to gravity (g) = 9.8 m/s²
- Time (t) = 2 - 1 = 1 s
- Height (h) =?
<h3>How to determine the distance the object will fall during the 2nd seconds</h3>
The distance the object will fall during the 2nd seconds can be obtained as follow:
h = ut + ½gt²
h = (0 × 1) + (½ × 9.8 × 1²)
h = 0 + 4.9
h = 4.9 s
Thus, the distance the object will during the 2nd seconds is 4.9 m
Learn more about motion under gravity:
brainly.com/question/22719691
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