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1 year ago

Line CT and line SM intersect at point A. What is the relationship between angle CAM and angle SAT?

1 answer:

8 0

The relationship between angle CAM and angle SAT is that angle CAM and angle TAS are vertical angles that are congruent.

<h3>Line and angles</h3>

A line is defined as the shortest distance between two point while the point where two lines meet is an angle.

Given two lines CT and SM, if these two lines meet at a point A, they form the angles SAM, SAT, SAC and MAT

From the diagram that will be formed, the two lines form angles at a point X. This shows that the angles CAM and SAT are congruent (vertically opposite)

Hence the relationship between angle CAM and angle SAT is that angle CAM and angle TAS are vertical angles that are congruent.

Learn more on vertical angles here: brainly.com/question/14362353

#SPJ1

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Two sections of a class took the same quiz. Section A had 15 students who had a mean score of 80, and Section B had 20 students

Nezavi [6.7K]

Answer: A. 85.7

Step-by-step explanation:

Given : Two sections of a class took the same quiz.

Section A had 15 students who had a mean score of 80, and Section B had 20 students who had a mean score of 90.

We know that , $\text{Mean}=\dfrac{\text{Sum of observations}}{\text{No. of observations}}$

Then , for section A :

$\text{Mean score }=\dfrac{\text{Sum of scores in sec A}}{\text{No. of students}}$

$\Rightarrow\ 80=\dfrac{\text{Sum of scores in sec A}}{15}\\\\\Rightarrow\ \text{Sum of scores in sec A}=80\times15=1200$

Similarly in Section B, $\text{Sum of scores in sec B}=90\times20=1800$

Total scores = Sum of scores in sec A+Sum of scores in sec B

=1200+1800=3000

Total students = Students in sec A +Students in sec B

=15+20=35

Now , the mean score for all of the students on the quiz = $\dfrac{\text{Total score}}{\text{Total students}}$

$=\dfrac{3000}{35}=85.7142857143\approx85.7$

Hence, the approximate mean score for all of the students on the quiz = 85.7

Thus , the correct answer is option A. 85.7.

7 0

2 years ago

Does anyone know how to do this? And can you also help me with this problem, thank you :)

GenaCL600 [577]

Multiply equation(2) with 4 so that coefficient of become same in both the equations(You can make coefficient of y same and can follow the following procedure.)
* Subtract (3) from (1)
* Divide both sides by -19
*Subtract 21 from both sides.
*Divide both sides by 4
so the solution is x= 3 and y= -7
Hope I helped you :)

6 0

3 years ago

A high school of 350 students offers biology and chemistry courses. 213 students are enrolled in biology while 155 students are

NNADVOKAT [17]

350 - 213 - 155 + 78 = 60 students not in either

4 0

3 years ago

Express with radical signs instead of fractional exponents. Rationalize the denominator.

CaHeK987 [17]

$x^{\frac{1}{2}} = \sqrt[2]{x}$ and $3^{-\frac{1}{2}} = \frac{1}{3^{\frac{1}{2}} } = \frac{1}{\sqrt[2]{3}}$ so

$3^{-\frac{1}{2}} x^{\frac{1}{2}} = \frac{1}{\sqrt{3}} \cdot \sqrt{x} = \frac{\sqrt{x}}{\sqrt{3}}$

and you rationalize denominator by multiplying numerator and denominatr by $\sqrt{3}$ so that gives--

$\frac{\sqrt{x}}{\sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}} = \frac{\sqrt{3x}}{3}$

Your answer is $\frac{\sqrt{3x}}{3}$

5 0

2 years ago

The complex zeros of the following polynomial function. Write f in factored form.

zavuch27 [327]

Answer: $\bold{x=-3\qquad x=\dfrac{3+3i\sqrt3}{2}\qquad x=\dfrac{3-3i\sqrt3}{2}}$

Step-by-step explanation:

The formula for factoring a cubic is:

a³ + b³ = (a + b)(a² - ab + b²)

f(x) = x³ + 3³

= (x + 3)(x² - 3x + 9)

To find the zeros, set each factor equal to zero and solve.

0 = x + 3 0 = x² - 3x + 9

-3 = x use quadratic formula

$x^2-3x+9\quad \rightarrow \quad a=1, b=-3, c=9\\\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\\\x=\dfrac{-(-3)\pm\sqrt{(-3)^2-4(1)(9)}}{2(1)}\\\\\\x=\dfrac{3\pm\sqrt{9-36}}{2}\\\\\\x=\dfrac{3\pm\sqrt{-27}}{2}\\\\\\x=\dfrac{3\pm3i\sqrt{3}}{2}$

Answer:

$x=-3\qquad x=\dfrac{3+3i\sqrt3}{2}\qquad x=\dfrac{3-3i\sqrt3}{2}$

7 0

3 years ago