Answer:
w = 6
Step-by-step explanation:
5w-26 = - 4 (w - 7) multiply -4 through
5w - 26 = - 4w + 28 add 4w to each side to cancel it out on the right
5w + 4w - 26 = 28
9w - 26 = 28 Now add 26 to each side
9w - 26 + 26 = 28 + 26
9w = 54 Now divide each side by 9
(9w)/9 = 54/9
w = 6
Bill and Joe have 60 dollars between them. Bill has half as much as Joe.
so Bill = B and Joe = J
20 (B) + 40 (J) = 60
Bill has half the amount of Joe, and so 40/2 = 20
subtract 60 from 20 (the answer for Bill) and you get 40, (the answer for Joe)
hope this helps
Answer:
1: C(n) = 2.50 + 16n
2: $66.50
Step-by-step explanation:
Part 1
Each ticket costs $16 per person. If tickets for n persons were purchased, the total cost would be 16n.
There is also a one-time service fee of $2.50 that must be paid. Thus, for n tickets the total cost is
C(n) = 2.50 + 16n
Part 2
For n = 4, the expression evaluates to
C(4) = 2.50 + 16 (4) = $66.50
Sixty two is your answer you’re adding all the sides
Answer:
<em>Two possible answers below</em>
Step-by-step explanation:
<u>Probability and Sets</u>
We are given two sets: Students that play basketball and students that play baseball.
It's given there are 29 students in certain Algebra 2 class, 10 of which don't play any of the mentioned sports.
This leaves only 29-10=19 players of either baseball, basketball, or both sports. If one student is randomly selected, then the propability that they play basketball or baseball is:

P = 0.66
Note: if we are to calculate the probability to choose one student who plays only one of the sports, then we proceed as follows:
We also know 7 students play basketball and 14 play baseball. Since 14+7 =21, the difference of 21-19=2 students corresponds to those who play both sports.
Thus, there 19-2=17 students who play only one of the sports. The probability is:

P = 0.59