1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
stiks02 [169]
3 years ago
8

This

Chemistry
1 answer:
timama [110]3 years ago
8 0

Answer:

4.2 Liters (2 sig-figs)

Explanation:

Apply Boyles Law ... P₁V₁ = P₂V₂

P₁ = 712 Torr      P₂ = 3560 Torr

V₁ = 21.0L           V₂ = ?

P₁V₁ = P₂V₂ => V₂ = P₁V₁/P₂ = (712Torr)(21.0L)/(3560Torr) = 4.2 Liters (2 sig-figs)

You might be interested in
Mr Singh is cooking using wo pans of oiling water. Both pans are made of steel, but one pan has a much thicker base than the oth
Sholpan [36]

Answer:

See explanation

Explanation:

When either pan is heated, energy is transferred via conduction. Conduction is the process by which heat is transferred through a material, the average position of the particles remaining the same.

When the pans are heated, the particles in each pan vibrate faster and transfer this energy rapidly to neighboring particles.

The pan with a thicker base has more particles in it than the pan with lighter weight base. Note that, The rate of heat transfer is inversely proportional to the thickness of the material in question. Hence, the thicker the base, the more the number of particles present and the longer the time it takes for the food to cook.

6 0
3 years ago
Consider the following reaction:
adell [148]

Answer:

1. d[H₂O₂]/dt = -6.6 × 10⁻³ mol·L⁻¹s⁻¹; d[H₂O]/dt = 6.6 × 10⁻³ mol·L⁻¹s⁻¹

2. 0.58 mol

Explanation:

1.Given ΔO₂/Δt…

    2H₂O₂     ⟶      2H₂O     +     O₂

-½d[H₂O₂]/dt = +½d[H₂O]/dt = d[O₂]/dt  

d[H₂O₂]/dt = -2d[O₂]/dt = -2 × 3.3 × 10⁻³ mol·L⁻¹s⁻¹ = -6.6 × 10⁻³mol·L⁻¹s⁻¹

 d[H₂O]/dt =  2d[O₂]/dt =  2 × 3.3 × 10⁻³ mol·L⁻¹s⁻¹ =  6.6 × 10⁻³mol·L⁻¹s⁻¹

2. Moles of O₂  

(a) Initial moles of H₂O₂

\text{Moles} = \text{1.5 L} \times \dfrac{\text{1.0 mol}}{\text{1 L}} = \text{1.5 mol }

(b) Final moles of H₂O₂

The concentration of H₂O₂ has dropped to 0.22 mol·L⁻¹.

\text{Moles} = \text{1.5 L} \times \dfrac{\text{0.22 mol}}{\text{1 L}} = \text{0.33 mol }

(c) Moles of H₂O₂ reacted

Moles reacted = 1.5 mol - 0.33 mol = 1.17 mol

(d) Moles of O₂ formed

\text{Moles of O}_{2} = \text{1.33 mol H$_{2}$O}_{2} \times \dfrac{\text{1 mol O}_{2}}{\text{2 mol H$_{2}$O}_{2}} = \textbf{0.58 mol O}_{2}\\\\\text{The amount of oxygen formed is $\large \boxed{\textbf{0.58 mol}}$}

8 0
3 years ago
The technology in the picture produces which energy conversion
BARSIC [14]
D) kinetinc to electric
7 0
3 years ago
Read 2 more answers
A 0.530 M Ca(OH)2 solution was prepared by dissolving 36.0 grams of Ca(OH)2 in enough water. What is the total volume of the sol
Gekata [30.6K]

Answer:

0.917

Explanation:

3 0
3 years ago
Determine the number of protons, electron and neutrons present in an atom of magnesium
Elena L [17]
Protons= 12, Electrons= 12, neutrons= 12
5 0
3 years ago
Other questions:
  • Two steel containers of equal volume contain two different gases at the same temperature. the first container holds 1.3 moles of
    6·1 answer
  • A glycosidic bond between two monosaccharides can also be classified as a(n) ________.
    13·1 answer
  • If Na was to form a 2 ion, from what orbital subshell would the second electron be lost?
    10·1 answer
  • Compound B, C6H12O2, was found to be optically active, and it was oxidized to an optically active carboxylic acid A, by Ag (aka,
    13·1 answer
  • Which of the following is an example of sound waves being reflected?
    15·1 answer
  • Write the empirical formula
    13·1 answer
  • PLS HELP ASAP WITH THIS SCIENCE HW
    13·1 answer
  • Which element would lose electrons during ionic bonding choose all that apply
    12·1 answer
  • What is the position of the dog
    11·2 answers
  • One quarter of chlorine is chlorine-37 and the rest is Chlorine-35. Calculate the average mass of chlorine
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!