Answer:
RxN: Na₂CO₃ (aq) + 2HCl (aq) → 2NaCl (aq) + H₂CO₃ (aq)
NIE: n/a
Explanation:
Step 1: Predict (Double Replacement)
Na₂CO₃ (aq) + HCl (aq) → NaCl (aq) + H₂CO₃ (aq)
Step 2: Balance
Na₂CO₃ (aq) + 2HCl (aq) → 2NaCl (aq) + H₂CO₃ (aq)
Step 3: Write Total Ionic Equation
2Na⁺ (aq) + CO₃²⁻ (aq) + 2H⁺ (aq) + 2Cl⁻ (aq) → 2Na⁺ (aq) + 2Cl⁻ (aq) + 2H⁺ (aq) + CO₃²⁻ (aq)
Step 4: Remove Spectator Ions
- Na⁺
- CO₃²⁻
- H⁺
- Cl⁻
Step 5: Write Net Ionic Equation
None.
NF3– 0.94– third
NCl3–0.12– second
NBr3–0.08– first
CF4–1.43– fourth
NBr3—NCl3—NF3—CF4
Lowest. Highest
Answer:
Most likely Spring or fall
Explanation:
Hope this helped:)
Sorry I'm late
M.P of oleic acid = 13 deg C
<span>B.Pof oleic acid = 360 deg C </span>
<span>(360 - 13) / 100 = 3.47 </span>
<span>So 1 deg O = 3.47 deg C </span>
<span>The scale do not start at 0 deg C, it starts at 13 deg C. So to convert deg C to deg O,
subtract 13 then divide by 3.47 </span>
<span>deg O = (deg C - 13) / 3.47 </span>
<span>convert O to C multiply by 3.47 then add 13 </span>
<span>deg C = (deg O x 3.47) + 13 </span>
<span>convert 0 deg C to deg O </span>
<span>deg O = (0 deg C - 13) / 3.47 </span>
<span>= - 3.75 deg O</span>
Hi! To find the amount of grams in 2.34 moles of cobalt, you must use the following equation:
2.34 mol Co * (58.93 g Co)/(1 mol Co)
The answer would therefore be 137.9 grams
