Question

Potassium permanganate (KMnO₄) has a solubility of 6.4 g/100 g of H₂O at 20°C and a curve of solubility vs. temperature that slopes upward to the right. How would you prepare a supersaturated solution of KMnO₄?

Answer 1

To make a supersaturated solution of, potassium permanganate KMn0₄ . We are also given some amazing data regarding this solid, including the fact that it can bind 6.4 grams per 100 grams of water at 20 degrees Celsius. As the temperature rises, capacity increases. The scalability curve's upward to right slope is thus mentioned. That implies that we get a curve when we plot temperature against capability. The argument is that when we boost temperature, we increase liability, even though we were not promised that something similar was linear. Thus, we must add as much than it can dissipate at room temperature in order to create a supersaturated solution. For every 100 grams of solution we use of 100 grams of water, we will need to add 6.4 grams of came in a Ford if we add additional van. Therefore, we need to employ 12 1 a, potassium permanganate, to create 200 milliliters or 200 grams of water. The salt must then completely dissolve by heating the solution above room temperature. If it cools down too quickly, we want to gradually bring the temperature down to room temperature. It will most likely precipitate if we put it in an ice bath. But if we gradually cool back down to 20 degrees, we ought to be able to keep around for a while.

To know more about KMn0₄ refer to brainly.com/question/14571753

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