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Dominik [7]
2 years ago
4

A bus leaves an intersection accelerating at +2.0 m/s2. Part A Where is the bus after 7.5 s?

Physics
1 answer:
irga5000 [103]2 years ago
3 0

The distance covered is 56 m.

<h3>What is acceleration?</h3>

We define acceleration as the rate at which the velocity changes with time. We can find the position of the bus by the use of the equations of kinematics.

Using the equation;

s = ut + 1/2at^2

u = initial velocity

a = acceleration

t = time taken

Since the bus started from rest u = 0 m/s

s = 1/2at^2

s = 0.5 * 2 * (7.5)^2

s = 56 m

Learn more about acceleration:brainly.com/question/12550364

#SPJ1

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Gravity affects atmospheric pressure true or false
Burka [1]

Answer:

false

Explanation:

5 0
3 years ago
Two boys with masses of 40 kg and 60 kg stand on a horizontal frictionless surface holding the ends of a light 10-m long rod. Th
kari74 [83]

When they meet the 40-kg boy will have moved a distance of 6 m.

Displacement of the 40 kg boy

The displacement of the 40 kg boy is calculated from the principle of center mass.

X(40 kg) = (60 x 10 m    +  40 x 0)/(40 kg + 60 kg)

X(40 kg) = (600)/(100) = 6 m

X(60 kg) = (60 x 0    +  40 x 10 m)/(40 kg + 60 kg)

X(60 kg) = (400)/(100) = 4 m

Thus, when they meet the 40-kg boy will have moved a distance of 6 m.

Learn more about center mass here: brainly.com/question/13499822

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7 0
2 years ago
Because Earth's rotation is gradually slowing, the length of each day increases: The day at the end of 1.0 century is 1.0 ms lon
stira [4]

Answer:

0.088 seconds

0.0880000273785 second

0.08800054757 seconds

Explanation:

In the question it is given each century adds 1 ms to a day due to the slowing rotation of the Earth

In 88 centuries the length of the first day of the year will be

88 × 1 = 88 ms = 0.088 seconds

1 ms = 1 century

1 century = 100 years × 365.25 days

⇒1 ms = 36525 days

1\ day=\frac{1}{365.25}=2.7378\times 10^{-5} ms=2.7378\times 10^{-8} s

Sum of the gain on the first day would be

0.088 + 2.7378×10⁻⁸ = 0.0880000273785 second

Sum of the gain on the second day would be

0.088 + 2.7378×10⁻⁸+2.7378×10⁻⁸ = 0.08800054757 seconds

7 0
3 years ago
A basketball is thrown for a free throw at 10m/s an angle of 20 degrees, makes it into the hoop and lands on the ground. Find th
Kruka [31]

Answer:

2

Explanation:

because uWU

6 0
3 years ago
Read 2 more answers
A 300 g block connected to a light spring with a force constant of k = 3 N/m is free to oscillate on a horizontal, frictionless
Usimov [2.4K]

Answer:

Time period, T = 1.98 seconds

Explanation:

It is given that,

Mass of the block, m = 300 g = 0.3 kg

Force constant of the spring, k = 3 N/m

Displacement in the block, x = 3 cm

Let T is the period of the motion of the block. The time period of the block is given by :

T=2\pi \sqrt{\dfrac{m}{k}}

T=2\pi \sqrt{\dfrac{0.3\ kg}{3\ N/m}}    

T = 1.98 seconds

So, the period of the motion of the block is 1.98 seconds. Hence, this is the required solution.

7 0
3 years ago
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