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hammer [34]
3 years ago
5

If the pressure acting on a given sample of an ideal gas at constant temperature is tripled, what happens to the volume of the g

as?
a) The volume is reduced to one-third of its original value.
b) The volume is reduced to one-ninth of its original value.
c) The volume remains constant.
d) The volume is increased by a factor of three times its original value.
e) The volume is increased by a factor of nine times its original value.
Physics
1 answer:
-Dominant- [34]3 years ago
3 0

If the pressure acting on a given sample of an ideal gas at constant temperature is tripled, the volume is reduced to one-third of its original value. <em>(a)</em>

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If you heat a fixed quantity of gas, which of the following statements are true?Check all that apply.a.The volume will always in
kherson [118]

Answer:

Explanation:

Given

there is fix Quantity of gas i.e. mass of gas is constant

From ideal gas Equation

PV=nRT

(a) volume always increases is not true as Pressure can also be increased .

(b)If Pressure is constant along with mass then as Temperature increases, Volume also increases.

(c)true , Product of Pressure and volume depends upon temperature thus it also increases with temperature.

(d)Density of gas may or may not increases

As density is \frac{mass}{volume}

volume may increase or decrease as temperature increase .

(e)false

as it clearly stated that quantity of fixed therefore there is no change in gas

8 0
3 years ago
Two rigid tanks of equal size and shape are filled with different gases. The tank on the left contains oxygen, and the tank on t
fredd [130]

Answer:

The number of oxygen molecules in the left container greater than the number of hydrogen molecules in the right container.

Explanation:

Given:

Molar mass of oxygen, M_O=32

Molar mass of hydrogen, M_H=2

We know ideal gas law as:

PV=nRT

where:

P = pressure of the gas

V = volume of the gas

n= no. of moles of the gas molecules

R = universal gs constant

T = temperature of the gas

∵n=\frac{m}{M}

where:

m = mass of gas in grams

M = molecular mass of the gas

∴Eq. (1) can be written as:

PV=\frac{m}{M}.RT

P=\frac{m}{V}.\frac{RT}{M}

        as: \frac{m}{V}=\rho\ (\rm density)

So,

P=\rho.\frac{RT}{M}

Now, according to given we have T,P,R same for both the gases.

P_O=P_H

\rho_O.\frac{RT}{M_O}=\rho_H.\frac{RT}{M_H}

\Rightarrow \frac{\rho_O}{32}=\frac{\rho_H}{2}

\rho_O=16\rho_H

∴The molecules of oxygen are more densely packed than the molecules of hydrogen in the same volume at the same temperature and pressure. So, <em>the number of oxygen molecules in the left container greater than the number of hydrogen molecules in the right container.</em>

5 0
3 years ago
Which sentence describes an example of sublimation?
k0ka [10]

answer C is the correct one

7 0
3 years ago
An amateur player is about to throw a dart with an initial velocity of 15 meters/second onto a dartboard that is at a distance o
Minchanka [31]

Answer:

B. 0.16 m

Explanation:

The vertical distance by which the player will miss the target is equal to the vertical distance covered by the dart during its motion.

Since the dart is thrown horizontally, the initial vertical velocity is zero:

v_y = 0

While the horizontal velocity is

v_x = 15 m/s

The horizontal distance covered is

d_x = 2.7 m

Since the dart moves by uniform motion along the horizontal direction, the time it takes for covering this distance is

t=\frac{d_x}{v_x}=\frac{2.7 m}{15 m/s}=0.18 s

along the vertical direction, the motion is a uniformly accelerated motion with constant downward acceleration g=9.8 m/s^2, so the vertical distance covered is given by

d_y = \frac{1}{2}gt^2=\frac{1}{2}(9.8 m/s^)(0.18 s)^2=0.16 m

8 0
4 years ago
Question 4
Minchanka [31]

Answer:

C

Explanation:

3 0
3 years ago
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