Answer:
60 000 J
Explanation:
The PE will be converted to KE entirely (if the lowest point is ground level)
Answer:
Petametres; 41 Pm
Explanation:
A measurement should use units that give a number between 0.1 and 1000.
The measure that astronomers use is the light year — the distance that light travels in one year.
In those units, the distance is 4.3 light years.
We can calculate the distance in SI units.
In SI, we should measure the distance in petametres (1 Pm = 10¹⁵ m)
Thus, the distance to the nearest star is 41 Pm.
Answer:
a)n= 3.125 x electrons.
b)J= 1.515 x A/m²
c) =1.114 x m/s
d) see explanation
Explanation:
Current 'I' = 5A =>5C/s
diameter 'd'= 2.05 x m
radius 'r' = d/2 => 1.025 x m
no. of electrons 'n'= 8.5 x
a) the amount of electrons pass through the light bulb each second can be determined by:
I= Q/t
Q= I x t => 5 x 1
Q= 5C
As we know that: Q= ne
where e is the charge of electron i.e 1.6 x C
n= Q/e => 5/ 1.6 x
n= 3.125 x electrons.
b) the current density 'J' in the wire is given by
J= I/A => I/πr²
J= 5 / (3.14 x (1.025x )²)
J= 1.515 x A/m²
c) The typical speed'' of an electron is given by:
=
=1.515 x / 8.5 x x |-1.6 x |
=1.114 x m/s
d) According to these equations,
J= I/A
= =
If you were to use wire of twice the diameter, the current density and drift speed will change
Increase in the diameter increase the cross sectional area and decreases the current density as it has inverse relation.
Also drift velocity will decrease as it is inversely proportional to the area