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1 year ago

The discovery of ribozymes provide evidence that life on the early earth may have been based on:_________

1 answer:

8 0

The discovery of ribozymes provide evidence that life on the early earth may have been based on RNA world hypothesis.

<h3>Origins of Life and the RNA World</h3>

We must think about how these mechanisms developed during evolution in order to completely comprehend the processes taking place in modern living cells.

The production of genetic information, which today requires incredibly complicated machinery and travels from DNA to protein via an intermediary called RNA, is the most fundamental of all such issues.

<h3>How did this equipment come to be? </h3>

One theory holds that there was an RNA world on Earth before contemporary cells emerged. This is the hypothesis.

RNA was a genetic information repository and a catalyst for chemical reactions in the earliest cells.

Proteins took over as the main catalytic and structural component of cells considerably earlier in the evolutionary process than DNA, which didn’t become the major genetic component until much later. If this hypothesis is correct, the departure from the RNA world was never truly complete.

To know more about RNA World visit:

brainly.com/question/25979866

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If the area of an iron rod is 10 cm by 0.5 cm and length is 35 cm. Find the value of resistance, if 11x10^-8 ohm.m be the resist

malfutka [58]

Answer:

Resistance of the iron rod, R = 0.000077 ohms

Explanation:

It is given that,

Area of iron rod, $A=10\ cm\times 0.5\ cm=5\ cm^2 = 0.0005\ m^2$

Length of the rod, L = 35 cm = 0.35 m

Resistivity of Iron, $\rho=11\times 10^{-8}\ \Omega-m$

We need to find the resistance of the iron rod. It is given by :

$R=\rho\dfrac{L}{A}$

$R=11\times 10^{-8}\times \dfrac{0.35\ m}{0.0005\ m^2}$

$R=0.000077 \Omega$

So, the resistance of the rod is 0.000077 ohms. Hence, this is the required solution.

6 0

2 years ago

How much total work is done by the force in lifting the elevator from 0.0 m to 9.0 m?

aksik [14]

The total work is

(mass of the elevator, kg) x (9.8 m/s²) x (9.0 m) Joules .

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3 years ago

A record player turntable initially rotating at 3313 rev/min is braked to a stop at a constant rotational acceleration. The turn

Rus_ich [418]

Answer:

(A) It will take 22 sec to come in rest

(b) Work done for coming in rest will be 0.2131 J

Explanation:

We have given the player turntable initially rotating at speed of $33\frac{1}{3}rpm=33.333rpm=\frac{2\times 3.14\times 33.333}{60}=3.49rad/sec$

Now speed is reduced by 75 %

So final speed $\frac{3.49\times 75}{100}=2.6175rad/sec$

Time t = 5.5 sec

From first equation of motion we know that '

$\alpha =\frac{\omega -\omega _0}{t}=\frac{2.6175-3.49}{4}=-0.158rad/sec^2$

(a) Now final velocity $\omega =0rad/sec$

So time t to come in rest $t=\frac{0-3.49}{-0.158}=22sec$

(b) The work done in coming rest is given by

$\frac{1}{2}I\left ( \omega ^2-\omega _0^2 \right )=\frac{1}{2}\times 0.035\times (0^2-3.49^2)=0.2131J$

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2 years ago

You are doing an experiment to determine your reaction time. Your friend holds a ruler. You place your fingers near the sides of

olga2289 [7]

I'm guessing that you mean like this:
-- The ruler is held with zero at the bottom, and the centimeter markings
    increase as you go up the ruler.
-- You place your fingers with the ruler and the zero mark between them.
-- The number where you catch the ruler is the distance it has fallen.

Then, all we have to find is the time it takes for the ruler to fall 11.3 cm .

Here's the formula for the distance an object falls from rest
in a certain time:

Distance = (1/2) (gravity) (time)²

On Earth, the acceleration of gravity is 9.8 m/s².
So we can write ...

      11.2 cm = (1/2) (9.8 m/s²) (time)²
or
       0.112 meter = (4.9 m/s²) (time)²

Divide each side
by 4.9 m/s² : (0.112 m) / (4.9 m/s²) = time²

(0.112 / 4.9) sec² = time²

Square root
each side:    time = √(0.112/4.9 sec²)

= √ 0.5488 sec²

=    0.74 second (rounded)

4 0

3 years ago

Read 2 more answers

How long does it take the moon to go from full-moon phase to new-moon phase

Amiraneli [1.4K]

A complete cycle of phases is 29.531 days.
From full-moon to new-moon is half of that.

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3 years ago