Question

A 40.0 -kg box initially at rest is pushed 5.00 m along a rough, horizontal floor with a constant applied horizontal force of 130N . The coefficient of friction between box and floor is 0.300 . Find(a) the work done by the applied force.

Answer 1

The work done by the applied force = 650 J

Given the mass of the box = 40 kg

The displacement of the box on applying force = 5 m

Applied horizontal force = 130 N

The co-efficient of friction between box and floor is = 0.3

We have to find the work done by the applied force.

Work done by the applied force = Applied Force x Displacement of the box

                                                      = 130 N x 5 m

                                                      = 650 J

[Here the unit Nm is known as Joule(J) ]

We have the co-efficient of friction. So,

The force applied due to friction = Mass of the box x Co-efficient of friction                                                                   x Acceleration due to gravity

                                                      = 40 kg x 0.3 x 9.8

                                                      = 117.6 N

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