A 40.0 -kg box initially at rest is pushed 5.00 m along a rough, horizontal floor with a constant applied horizontal force of 13
1 answer:
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Answer:
11.25 amps
Explanation:
For transformers, the magnetic flux
Therefore;
Ф = Фmax (cosωt) = 0.21·(cos(5·t))
From Faraday's law of induction, we have;
ε = -N × dΦ/dt
Which gives;
dΦ/dt = -1.05(sin (5t) )
ε = -N × dΦ/dt = -50× -1.05(sin (5t) )
ε = 52.5(sin (5t) )
I = ε/R = 52.5(sin (5t) )/3.3 = 15.9091(sin (5t) ) amps
The peak current is therefore = 15.9091 amps
The rms current = Peak current /√2 = 15.9091/(√2) = 11.25 amps.
Answer:
Yes it is possible
Explanation:
When two equal magnitude forces are acting on the rod in opposite direction
Then the net force on the system is always zero in that case
so we will have
now for the system net torque due to these forces is given by
here we know that
= distance of the forces from reference about which torque is measured
so here we can say that net force is zero on the system while torque is not zero
in all such case object will rotate about a fixed position with change angular speed