3 years ago

How might a titration be different if a.1m base solution that produces 2 moles of hydroxide g?

Chemistry

1 answer:

Romashka [77]3 years ago

4 0

Use higher concentration of acid to produce 2 moles of hydrogen to form water

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Help please i dont know if it's right

makkiz [27]

D is the correct answer for your question. Maybe I am not sure.

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4 years ago

If a solution has virtually virtually no hydrogen ions, what type of pH does it have?

GrogVix [38]

Answer:

13: if thats one of the options

Explanation:

B/c for pH to be that high you have to have alot of OH ions and almost non H+. pH won't be 0 or 2 cuz that implies ALOT of H ions. pH wont be 7 cuz that implies we have 1*10^-7 H ions.

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3 years ago

Read 2 more answers

A weather balloon is inflated to a volume of 27.9L at a pressure of 732mmHg and a temperature of 30.1?C. The balloon rises in th

masya89 [10]

Answer:

45.4 L

Explanation:

Using Ideal gas equation for same mole of gas as

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

Given ,

V₁ = 27.9 L

V₂ = ?

P₁ = 732 mmHg

P₂ = 385 mmHg

T₁ = 30.1 ºC

T₂ = -13.6 ºC

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (30.1 + 273.15) K = 303.25 K

T₂ = (-13.6 + 273.15) K = 259.55 K

Using above equation as:

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

$\frac{{732}\times {27.9}}{303.25}=\frac{{385}\times {V_2}}{259.55}$

$\frac{385V_2}{259.55}=\frac{20422.8}{303.25}$

$148225V_2=6729708.26018$

Solving for V₂ , we get:

V₂ = 45.4 L

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4 years ago

Which tool was most likely used in a procedure if the lab report shows 300ml of water was used

maxonik [38]

A graduated cylinder, it measures the exact amount of liquid used.

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4 years ago

Flowing water eroding a limestone riverbed a Chemical Change b Physical Change

Galina-37 [17]

Answer:

physical change

I hope it's helps you

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3 years ago