How might a titration be different if a.1m base solution that produces 2 moles of hydroxide g?
1 answer:
You might be interested in
Answer : The value of for this reaction is,
Explanation :
The given chemical reaction is:
Now we have to calculate value of .
where,
= Gibbs free energy of reaction = ?
n = number of moles
= -389.8 kJ/mol
= -161.96 kJ/mol
= -137.2 kJ/mol
Now put all the given values in this expression, we get:
The relation between the equilibrium constant and standard Gibbs, free energy is:
where,
= standard Gibbs, free energy = -89.4 kJ/mol = -89400 J/mol
R = gas constant = 8.314 J/L.atm
T = temperature =
= equilibrium constant = ?
Now put all the given values in this expression, we get:
Thus, the value of for this reaction is,