Answer:
the answer is destructive interference
The most stable isotope would be lead-82.
<h2>In the name, iron(III) oxide, the (III) represents: D) the electrical charge of iron</h2><h2>
Explanation:</h2>
To attain stability the chemical bond is formed .
Chemical bond
It is a kind of linkage that binds one atom with the other .
The atoms do so in order to attain stable noble gas configuration .
To form chemical bond they either:
Loose electrons : when atoms loose electrons they acquire positive charge which is equal to the number of electrons lost .
Gain electrons: After gaining electrons they acquire negative charge which is equal to the number of electrons gained by an atom.
share electrons : With sharing no charges are develop .
<em>In the above asked question when iron combines with oxygen it forms iron oxide : where iron looses 3 electrons and oxygen gains 2 electrons .That is the reason ,III here represents the electrical charge of iron</em>
<span>3.68 liters
First, determine the number of moles of butane you have. Start with the atomic weights of the involved elements:
Atomic weight carbon = 12.0107
Atomic weight hydrogen = 1.00794
Atomic weight oxygen = 15.999
Molar mass butane = 4*12.0107 + 10*1.00794 = 58.1222 g/mol
Moles butane = 2.20 g / 58.1222 g/mol = 0.037851286
Looking at the balanced equation for the reaction which is
2 C4H10(g)+13 O2(g)→8 CO2(g)+10 H2O(l)
It indicates that for every 2 moles of butane used, 8 moles of carbon dioxide is produced. Simplified, for each mole of butane, 4 moles of CO2 are produced. So let's calculate how many moles of CO2 we have:
0.037851286 mol * 4 = 0.151405143 mol
The ideal gas law is
PV = nRT
where
P = Pressure
V = Volume
n = number of moles
R = Ideal gas constant ( 0.082057338 L*atm/(K*mol) )
T = absolute temperature (23C + 273.15K = 296.15K)
So let's solve the formula for V and the calculate using known values:
PV = nRT
V = nRT/P
V = (0.151405143 mol) (0.082057338 L*atm/(K*mol))(296.15K)/(1 atm)
V = (3.679338871 L*atm)/(1 atm)
V = 3.679338871 L
So the volume of CO2 produced will occupy 3.68 liters.</span>
173.1f is the answer I believe, please let me know if I'm wrong then I would try to make up for it
