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2 years ago

Phosphine (PH₃) reacts with borane (BH₃) as follows:

1 answer:

5 0

Phosphine (IUPAC name: phosphane) is a colorless, flammable, highly toxic compound with the chemical formula PH3, classed as a pnictogen hydride.

The lone pair is responsible for asymmetrical charge distribution and hence, PH3 is a polar molecule with non-polar covalent bonds.

<h3 /><h3>Is PH3 poisonous?</h3>

With traces of P 2H 4 present, PH 3 is spontaneously flammable in air (pyrophoric), burning with a luminous flame. Phosphine is a highly toxic respiratory poison, and is immediately dangerous to life or health at 50 ppm.

Learn more about PH3 here:

<h3>brainly.com/question/24657736</h3><h3 /><h3>#SPJ4</h3>

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Which actions would increase the rate at salt dissolves in water

agasfer [191]

I’m pretty sure the answer is stir the water

5 0

4 years ago

Read 2 more answers

State the periodic law, and explain its relation to electron configuration. (Use Na and K in your explanation.)

mina [271]

Answer:

Explanation:

The period law state that when elements are listed in order of their atomic numbers, the elements fall into recurring groups, so that there is a recurrence of similar properties at regular intervals.

Na and K in the periodic table fall into the same group, this is because they both have one electrons in their outermost shell.

Na 11 -1s2 2s2 2p6 3s1

K 19 - 1s2 2s2 2p6 3s2 3p6 4s1

They share similar chemical and physical properties. Na and K are very reactive metals, they can loose/donate their outermost electron to non metals in other to attain stable octet state.

The form ionic compound when they react with non metals.

5 0

3 years ago

In the first 22.0 s of this reaction, the concentration of HBr dropped from 0.590 M to 0.465 M . Calculate the average rate of t

Alex

This is an incomplete question, here is a complete question.

Consider the following reaction:

$2HBr(g)\rightarrow H_2(g)+Br_2(g)$

In the first 22.0 s of this reaction, the concentration of HBr dropped from 0.590 M to 0.465 M . Calculate the average rate of the reaction in this time interval.

Answer : The average rate of reaction is, $6.25\times 10^{-3}M/s$

Explanation :

The given chemical reaction follows:

$2HBr(g)\rightarrow H_2(g)+Br_2(g)$

The average rate of the reaction for disappearance of HBr is given as:

$\text{Average rate of disappearance of HBr}=-\frac{\Delta [HBr]}{\Delta t}$

where,

$C_2$ = final concentration of HBr = 0.465 M

$C_1$ = initial concentration of HBr = 0.590 M

$\Delta t$ = change in time = 22.0 s

Putting values in above equation, we get:

$\text{Average rate of reaction}=-\frac{(0.465-0.590)M}{20.0s}\\\\\text{Average rate of reaction}=6.25\times 10^{-3}M/s$

Hence, the average rate of reaction is, $6.25\times 10^{-3}M/s$

3 0

3 years ago

How to compare and contrast a solution of hydrogen chloriide gas in water and toluene?

Airida [17]

<span>The solute is the substance that is being dissolved while the solvent is the base that the solute is bring dissolved in. For example, in salt water, salt would be the solute that dissolves into the water, and the water is the solvent that the salt is being dissolved in.</span>

4 0

4 years ago

A stream of air (21 mole% o2, the rest n2) flowing at a rate of 10.0 kg/h is mixed with a stream of co2. the co2 enters the mixe

Zepler [3.9K]

Molecular weight of air = 29 g/mole, moles of air entering = 5/29 kgmoles/hr= 0.1724 kg moles/hr
Moles of N2= 0.21*0.1724=0.036 kg moles/hr, moles of N2= 0.79*0.1724= 0.1362 kgmoles/hr
Moles of CO2 can be calculated from gas law equation, n= PV/RT
V= 25 m3/hr= 25* 1000 L/hr, P= 2 bar = 2*0.9869 atm,=1.9738 atm R= 0.0821 L.atm/mole.K T= 100 deg.c =100+?273.15= 373.15K
n= number of moles of CO2= 1.9738*25*1000/ (0.0821*373.15) =1611 moles/hr= 1.611 kg moles/hr
total moles of mixture = 0.1724 +1.611 =1.7834 kg moles/hr
Moles % CO2 in the mixed stram = 100*1.611/1.7834 = 90.33%
Answer is 90.33%

6 0

3 years ago