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o-na [289]
4 years ago
10

Which of the following is considered an IT career? Financial Analyst Office Manager Structural Engineer Database Administrator

Physics
2 answers:
bagirrra123 [75]4 years ago
5 0

Answer:

d

Explanation:cuz

galben [10]4 years ago
4 0

Answer:

D database administrator

Explanation:

cause it makes sense

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Julie drives 100 mi to Grandmother's house. On the way to Grandmother's, Julie drives half the distance at 34.0 mph and half the
tester [92]

The concepts necessary to solve this problem are those given by the kinematic equations of motion. We will apply the speed as a unit of distance traveled in a given time.

The total distance of 50 miles is traveled with a speed of 34mph in the time T_1 and the distance of another 50 miles is traveled with a speed 66mph in the time T_2.

Determine the value of T_1 as follows.

t = \frac{d}{v} \rightarrow Where t=time, d=distance, v= Velocity

t = \frac{50miles}{34mph}

t = 1.471h

Determine the value of T_2 as

T_2 = \frac{50miles}{66mph}

T_2 = 0.7576h

Therefore the total time taken is

T_{Total} = T_1+T_2

T_{Total} = 1.471h+0.7576h

T_{Total} = 2.2286h

The above result is the total time taken to reach the grandmother's house

Now the average velocity is

v_{Avg} = \frac{100 miles}{2.2286h}

v_{Avg} = 44.87mph

Therefore the average speed on the way to grandmother's house is 44.87mph

3 0
4 years ago
Sound travels at a speed of 330 meters/second. If Denise hears a police siren 150 meters away, approximately how long did it tak
Zinaida [17]

Answer:

It went about 2 meters away

Explanation:

7 0
3 years ago
Serena Williams has an average serve speed of 47 m/s. Find the mass of the tennis ball if its kinetic energy is 65 J.
avanturin [10]

Answer:

That's about 12 kilometers per hour faster than the average female professional tennis player.

Explanation:

3 0
3 years ago
Two large parallel conducting plates carrying opposite charges of equal magnitude are separated by 2.20 cm. If the surface charg
bekas [8.4K]

Answer:

5.3\times 10^3 N/C

Explanation:

We are given that

Distance between plates=d=2.2 cm=2.2\times 10^{-2} m

1 cm=10^{-2} m

\sigma=47nC/m^2=47\times 10^{-9}C/m^2

Using 1 nC=10^{-9} C

We have to find the magnitude of E in the region between the plates.

We know that the electric field for parallel plates

E=\frac{\sigma}{2\epsilon_0}

E_1=\frac{\sigma}{2\epsilon_0}

E_2=\frac{\sigma}{2\epsilon_0}

E=E_1+E_2

E=\frac{\sigma}{2\epsilon_0}+\frac{\sigma}{2\epsilon_0}=\frac{\sigma}{\epsilon_0}

Where \epsilon_0=8.85\times 10^{-12}C^2/Nm^2

Substitute the values

E=\frac{47\times 10^{-9}}{8.85\times 10^{-12}}

E=5.3\times 10^3 N/C

Hence, the magnitude of E in the region between the plates=5.3\times 10^3 N/C

5 0
3 years ago
2) The position of a particle is given r(t) = A(cos wt i + sin wt f), where w is a constant. (a) Show that the particle moves in
olya-2409 [2.1K]

Answer:

Explanation:

r(t) = A(cos wt i + sin wt f)

= A cos wt i + A sin wt j

x = A cos wt

y = A sin wt

radius r

r² = x² + y² ( This is equation of a circle with radius r  )

=  A² cos² wt +A² sin² wt

= A²

r = A

radius r = A

b )

speed = dr/dt

v = - Aw sinwt i + Aw coswt j

magnitude of velocity

I v I= Aw √(sin²wt + cos²wt)

= Aw ( constant )

acceleration

= dv / dt = - Aw² cos wt - Aw² sinwt

magnitude of acceleration

I a I = Aw²

= r w²

d ) centripetal force = m acceleration

m w² A  

=

7 0
3 years ago
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