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o-na [289]
3 years ago
10

Which of the following is considered an IT career? Financial Analyst Office Manager Structural Engineer Database Administrator

Physics
2 answers:
bagirrra123 [75]3 years ago
5 0

Answer:

d

Explanation:cuz

galben [10]3 years ago
4 0

Answer:

D database administrator

Explanation:

cause it makes sense

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An object accelerating at 16 m/s/s doubles its mass and triples its net force acting on it. What will the new acceleration be? (
nataly862011 [7]

Answer:

24 m/s²

Explanation:

The given parameters are;

The initial acceleration of the object, a = 16 m/s²

Let 'm' represent the initial mass of the object

The initial force acting on the object, F = m × a

∴ F = 16 × m = 16·m

When the mass is doubled, we have;

The new mass of the object, m₂ = 2 × m = 2·m

When the net force acting on the object triples, we have;

The new net force acting on the object, F₂ = 3 × F = 3 × 16·m = 48·m

From F = m × a, we have;

a = F/m

∴ The new acceleration of the object, a₂ = F₂/m₂

From which, by plugging in the values, we have;

a₂ = 48·m/(2·m) = 24

The new acceleration of the object, a₂ = 24 m/s².

6 0
3 years ago
To calculate work done on an object, _____. A. multiply the force in the direction of motion by the distance the object moved B.
o-na [289]
I believe your answer would be B, hope it helps

6 0
3 years ago
Read 2 more answers
Is this true or false a seismograph records the air movements caused by sseismic waves
olasank [31]
The answer to this question is False.
6 0
3 years ago
Three deer, a, b, and c, are grazing in a field. deer b is located 62.1 m from deer a at an angle of 54.3 ° north of west. deer
sveticcg [70]

by cosine law we know that

c^2 = a^2 + b^2 - 2 abcos\theta

\theta = 180 - 54.3 - 79.1 = 46.6 degree

now using above equation

93.8^2 = 62.1^2 + b^2 - 2*62.1*b * cos46.6

4942.03 = b^2 - 85.34 b

b^2 - 85.34b - 4942.03 = 0

by solving above quadratic equation we have

b = 124.9 m

so it is at distance 124.9 m from deer a

4 0
3 years ago
Based on the replacement reaction, what would the products of the reaction be?
cricket20 [7]

Answer:

\rm Be(OH)_2 and \rm (NH_4)_2 SO_4. The missing ion would be \rm OH^{-}.

Explanation:

In a double replacement reaction, two ionic compounds exchange their ions to produce two different ionic compounds.

In this question, the two ionic compounds are:

  • \rm BeSO_4, and
  • \rm NH_4 OH.

In particular,

  • \rm BeSO_4 is made up of \rm Be^{2+} ions and \rm {SO_4}^{2-} ions, while
  • \rm NH_4 OH is made up of \rm {NH_4}^{+} ions and \rm OH^{-} ions.

In a binary ionic compound, cations (positive ions) can only bond to anions (negative ions.)

  • \rm Be^{2+} is a cation. In \rm BeSO_4, \rm Be^{2+} was bounded \rm {SO_4}^{2-} anions. During the reaction, it bonds with \rm OH^{-} anions to produce \rm Be(OH)_2.
  • \rm {NH_4}^{+} is also a cation. In \rm NH_4 OH, \rm {NH_4}^{+} was bounded to \rm OH^{-} ions. During the reaction, it bonds with \rm {SO_4}^{2-} anions to produce \rm (NH_4)_2 SO_4.

Hence, the two products will be \rm Be(OH)_2 and \rm (NH_4)_2 SO_4.

Note that charges on the ions must balance. For example, a \rm Be^{2+} ion carries twice as much charge as an \rm {NH_4}^{+} ion. As a result, each \rm Be^{2+} ion would bond with twice as many \rm OH^{-} ions as \rm {NH_4}^{+} would in \rm NH_4 OH.

4 0
3 years ago
Read 2 more answers
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