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Helga [31]
2 years ago
15

The creation and study of new and very massive elementary particles is an important part of contemporary physics. To create a pa

rticle of mass M requires an energy M c² . With enough energy, an exotic particle can be created by allowing a fast-moving proton to collide with a similar target particle. Consider a perfectly inelastic collision between two protons: an incident proton with mass mp , kinetic energy K , and momentum magnitude p joins with an originally stationary target proton to form a single product particle of mass M . Not all the kinetic energy of the incoming proton is available to create the product particle because conservation of momentum requires that the system as a whole still must have some kinetic energy after the collision. Therefore, only a fraction of the energy of the incident particle is available to create a new particle.(b) This problem can be alleviated by using colliding beams as is the case in most modern accelerators. Here the total momentum of a pair of interacting particles can be zero. The center of mass can be at rest after the collision, so, in principle, all the initial kinetic energy can be used for particle creation. Show thatM c² =2 m c² ((1+1/km /c²))where K is the kinetic energy of each of the two identical colliding particles. Here, if K>>m c² , we have M directly proportional to K as we would desire.
Physics
1 answer:
dimaraw [331]2 years ago
4 0

Consider a collision between two protons that is perfectly inelastic: an incident proton with mass m(p), kinetic energy K, and momentum magnitude p combines with a target proton that was initially stationary to form a single product particle with mass M.

Now,

In this case, the problem is alleviated by using colliding beams.

A pair of interacting particles' combined momentum may be zero.

After the collision, the center of mass is at rest.

Therefore, all the initial kinetic energy can be used to create particles.

Let K be the kinetic energy of each of the two identical colliding particles.

Therefore, the energy released by the two colliding beams are:

E₁ = K + mc² and E₂ = K + mc²

In the final state,

E(f) = Mc² where M is the new mass of the single product after the collision.

By conservation of energy,

E₁ + E₂ =E(f)

K + mc² + K + mc² = Mc²

2K + 2mc² = Mc²

Taking 2mc² common, we get

Mc² = 2mc²[ 1 + (K/mc²)]

Learn more about collision here:

brainly.com/question/12644900

#SPJ4

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someone help pls. Two students, Mia and Peter, leave school to meet at the local coffee shop. Peter decides to jog to the coffee
cluponka [151]

Answer:

1) The distance further it takes Peter to arrive at the Coffee shop than Mia is 1.24 km

2) Mia's average speed is 6.00 km/hour

Peter's average speed is 8.48 km/hour

4) Mia's average velocity = Peter's average velocity = 6.00 km/hour

Explanation:

The given information from the diagram are;

The distance Peter jogs from school to the flower shop = 2.00 km

The distance Peter jogs from the Flower shop to the Coffee shop = 2.24 km.

The distance Mia walks from school directly to the Coffee shop = 3.00 km

The time it takes both Peter and Mia to arrive at the coffee shop = 30 minutes = 0.5 hour

1) The total distance Peter travels from school to the Coffee shop = 2.00 km + 2.24 km = 4.24 km

The distance Mia travels from school to the Coffee shop = 3.00 km

The distance further it takes Peter to arrive at the Coffee shop than Mia = 4.24 km - 3.00 km = 1.24 km

The distance further it takes Peter to arrive at the Coffee shop than Mia = 1.24 km

2) Average \ speed = \dfrac{Total \ distance \ traveled}{Total \ time \ taken \  in \ the \ journey}

Therefore, \ Mia's \ average \ speed = \dfrac{3.00 \ km}{0.5 \ hour}= 6.00 \ km/hour

Mia's average speed = 6.00 km/hour

Peter's \ average \ speed = \dfrac{4.24 \ km}{0.5 \ hour}= 8.48 \ km/hour

Peter's average speed = 8.48 km/hour

4) Average \ velocicty = \dfrac{Displacement }{Time  \ taken}

The displacement from the School to the Coffee shop is 3.00 km for both Mia and Peter

The time it takes both Peter and Mia to arrive at the Coffee shop from the school is 30 minutes = 0.5 hour

Therefore, \ Mia's \ average \ velocity = \dfrac{3.00 \ km}{0.5 \ hour}= 6.00 \ km/hour

Mia's average velocity = 6.00 km/hour

Peter's \ average \ velocity = \dfrac{3.00 \ km}{0.5 \ hour}= 6.00 \ km/hour

Therefore, Peter's average velocity is also = 6.00 km/hour

6 0
3 years ago
to advance in time the evolution of temperature of the atmosphere at any given point in the globe, models calculate the temperat
Natasha_Volkova [10]
  • The complexity of Earth is beyond the capabilities of computer simulations.
  • Numerous assumptions that must be made by computer models have a big impact on the forecasts they produce.
  • A computer model can incorporate historical climate data, but it is not possible to draw assumptions about future climates using this data in any way.
  • A computer model cannot distinguish between anthropogenic climate change and natural climatic fluctuations.
<h3>How precise are temperature forecasts made by climate models?</h3>

The forecasting of global surface temperatures is one of the most significant results of climate models.

Scientists evaluate the effectiveness of their models by contrasting observations of the Earth's climate with predictions of future temperatures and "hindcasts" of past temperatures. Then, by comparing specific climate models and the average of all models to actual warming, scientists may determine whether temperature projections are accurate.

Researchers can have more faith that models can effectively predict future changes in the same factors if they successfully simulate the climate response in the past.

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8 0
1 year ago
Find the weight of an astronaut whose mass is 75 kg on the moon
gladu [14]
The formula for weight is always weight=mass X gravitational field strength.
We already know the mass is 75kg.
The gravitational field strength on the moon is 1.6N. To find out the weight, we can substitute these values in to the formula.
Weight=75 X 1.6
Weight= 120N
Weight is measured on Neutons as it is a force.
8 0
3 years ago
A copper wire has a square cross section 2.0 mm on a side. The wire is 5.0 m long and carries a current of 2.0 A. The density of
kondor19780726 [428]

Answer:

30.22 hours

Explanation:

Given data:

A= l² = (2 x 10^{-3})² = 4 x 10^{-6} m²

Length 'L' = 5m

current 'I' = 2 A

density of free electrons 'n'= 8.5 x 10^{28} /m³

Current Density 'J' = I/ A

J= 2/4 x 10^{-6}

J= 5 x 10^{5} A/m²

We can determine the  time required for an electron to travel the length of the wire by

T= L/ Vd

Where,

L is length and Vd is drift velocity.

Vd can be defined by J/ n|q|

where,

n is the charge-carrier number density

|q| is is the charge carried by each charge carrier =>1.6 x 10^{-19}C

T= L/ Vd

Therefore,

T= L . n|q| / J

T= (4 x 8.5 x 10^{28} x |1.6 x 10^{-19}|)/5 x 10^{5}

T= 108800 seconds =>1813.33 minutes

Converting minute into hours:

T= 30.22 hours

Thus, time that is required for an electron to travel the length of the wire is 30.22 hours

4 0
3 years ago
Which of the following is a consequence of the special theory of relativity?
aleksandr82 [10.1K]

Answer:

D.

Explanation:

Specifically, Special Relativity showed us that space and time are not independent of one another but can be mixed into each other and therefore must be considered as the same object, which we shall denote as space-time. The consequences of space/time mixing are: time dilation. and length contraction.

3 0
2 years ago
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