Answer:
454.3 g.
Explanation:
1.0 mol of CaO liberates → – 64.8 kJ.
??? mol of CaO liberates → - 525 kJ.
∴ The no. of moles needed = (1.0 mol)(- 525 kJ)/(- 64.8 kJ) = 8.1 mol.
<em>∴ The no. of grams of CaO needed = no. of moles x molar mass</em> = (8.1 mol)(56.077 g/mol) = <em>454.3 g.</em>
Answer:
Nov 28, 2019 - These templates were designed to help get you started. ... of each opportunity is clear to see, because the ones you send match not only my interests but my abilities. What you do is really motivating and keeps me uplifted in my job ... to thank you for all the support you've shown me throughout my career, ...
Explanation:
Answer:
Explanation:
The triple point of carbon dioxide is 5.11 atmosphere at -56.6 degree celsius . At pressure greater than 5.11 , solid carbon dioxide liquefies , as it is warmed. At pressure lesser than 5.11 atmosphere , it will go into gaseous state without liquefying . Excessive pressure helps liquification process.
So maximum pressure required is 5.11 atmosphere. Beyond this pressure , solid CO2 will liquify.
Answer:
- motors that run on electricity
- tires that improve gas mileage
Explanation:
The transportation is a major polluter of the air. The big problem with it is that it is necessary for the humans to be able to live and function properly, as the trade is happening through it, thus it is crucial for the economy. In order to stop or reduce the negative impact on the air quality, there are some solutions which can help. The motors that can run on electricity are an excellent method, as the production of electricity is not polluting the are as the fossil fuels are. The only problem is that this type of motors are still very expensive, so once their price is on pair with the combustion motors they can be used. Tires that are able to increase the efficiency of the transportation means can also be useful, as they will be able to reduce the amount of pollutants released into the atmosphere, because the transportation will use less fossil fuels for the same mileage.
Answer:
1/10 or 0.1
Explanation:
Quantities at which equivalence can be obtained are:
95, 96, 97, 98, 99, 100, 101, 102, 103, 104
Number of quantities = N = 10
Probability that the equivalency is obtained exactly at 100 mL can be calculated as follows:
P(X = 100) = (Number of favourable outcomes) / (Total Number of Outcomes)
P(X = 100) = 1/10
P(X = 100) = 0.1
