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1 year ago

Caffeine concentration is 1.99 mg/oz how many cans would be leathal if 10g was leathal and there where 12oz in a can

1 answer:

5 0

The number of cans that would be considered lethal if 10g was lethal and there where 12oz in a can is 419 cans.

<h3>How to convert mass?</h3>

According to this question, caffeine concentration is 1.99 mg/oz.

1.99 milligrams can be converted to grams as follows:

1.99milligrams ÷ 1000 = 0.00199grams

This means that 0.00199grams per oz is the caffeine concentration.

If there were 12 oz in a can, then, 0.00199grams × 12 = 0.02388 grams in 1 can.

This means that if 10grams is considered lethal, 10grams ÷ 0.02388 grams = 419 cans would be lethal for consumption.

Therefore, the number of cans that would be considered lethal if 10g was lethal and there where 12oz in a can is 419 cans.

Learn more about conversion factor at: brainly.com/question/14479308

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An automobile with a mass of 1250 kg accelerates at a rate of 4 m/sec2 in the forward direction. What is the net force acting on

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$\large{\underline{\underline{\maltese{\pink{\pmb{\sf{ \; Question \; :- }}}}}}}$

An automobile with a mass of 1250 kg accelerates at a rate of 4 m/sec² in the forward direction. What is the net force acting on the automobile?

_________________________________________

$\large{\underline{\underline{\maltese{\green{\pmb{\sf{ \; Given\; :- }}}}}}}$

➢ Mass of the automobile = 1250 kg
➢ Acceleration of the body = 4m/sec²

$\large{\underline{\underline{\maltese{\orange{\pmb{\sf{ \; To \: Find \; :- }}}}}}}$

Net force acting on the automobile = ?

$\large{\underline{\underline{ \bigstar{{\pmb{\sf{ \; Concept \: and \: Formula \: Used \; :- }}}}}}}$

➯ Force is defined as the product of the mass of the body and its acceleration.

$\bigstar \: \small{ \fbox {\textsf {\textbf{F = ma}}}}$

Where :

F = Force
m = Mass of the body
a = acceleration due to gravity

$\large{\underline{\underline{ \bigstar{{\pmb{\sf{ \; Substituting \: the\: Given\: Values :- }}}}}}}$

$⇝ \: \: \small \textsf {\textbf{ F = (1250 × 4) N }}$

$⇝ \: \: \small \textsf {\textbf{ F = 5000 N }}$

$\large{\underline{\underline{ \bigstar{{\pmb{\sf{ \; Therefore \; :- }}}}}}}$

❝ The net force acting on the automobile is 5000 N. ❞

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