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almond37 [142]
3 years ago
6

Chemistryyyyyyyyyyyyyyyyyyyyyyyyyyyyyyy

Chemistry
1 answer:
mrs_skeptik [129]3 years ago
5 0
Water is your answer!!!!!!!!!
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A chemist must prepare 400 mL of 1.00M aqueous aluminum sulfate working solution. He'll do this by pouring out 1.82 mol/L aqueou
Digiron [165]

Answer:

219.78 mL of the stock solution are needed

Explanation:

First, we take a look at the desired Al2(SO4)3 working solution. We are told that the we need 400 mL of an aqueous aluminum sulfate solution 1.0 M. Let's see how many moles of the compound we have in the desired volume:

1000 mL Al2(SO4)3 solution ----- 1 mole of Al2(SO4)3

400 mL Al2(SO4)3 solution ----- x = 0.4 moles of Al2(SO4)3

To reach the desired concentration in the working solution we need 0.4 moles of Al2(SO4)3 in 400 mL, so we calculate the volume of the stock solution needed to prepare the working solution:

1.82 moles Al2(SO4)3/L = 1.82 M → This is the molar concentration of the stock solution.

1.82 moles of Al2(SO4)3 ----- 1000 mL

0.4 moles of Al2(SO4)3 ----- x = 219.78 mL

So, if we take 219.78 mL of the 1.82 M stock solution, we put it in a graduated cylinder and we dilute it to 400 mL, we would obtain a 1.0 M Al2(SO4)3 solution.

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3 years ago
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How many oxygen molecules are in 22.4 liters of oxygen gas at 273 K and 101.3 kPa?
lora16 [44]
The answer would be 6.023 x 10E23
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Help please ASAP 10 point
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What would be the result on the Insect population if the Bats and Mice were removed?
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We wouldn't have Coronavirus

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