1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Elanso [62]
3 years ago
10

Cracking the periodic table code why aren't the elements listed in alphabetical order answer key

Chemistry
2 answers:
VladimirAG [237]3 years ago
8 0
<span>They could be arranged in alphabetical order but that wouldn't tell you much about their chemistry. In the periodic table, the elements are arranged according to their atomic number. Notice how the atomic number increases as you move across the table. Normally, the higher the atomic number, the heavier the element. So lead (Pb), atomic number 82 is heavier than tin (Sn) atomic number 50.</span>
finlep [7]3 years ago
4 0

The elements in the periodice table are not listed in alphabetical order, because the arragement in rows (periods) and columns (groups or familes), in increasing order of atomic number (number of protons of the atoms) permits to explain similarities among the elements, trend in some properties, and even predict properties of unknown elements.


For example, the elements of the first group (family), called alkaline metals, all have 1 valence electron, have similar physical properties (ductibility, malleability, luster, thermal and electricity conductivity), react in similar way with water, show a trend in the atomic radii and in the ionization energy.


You can tell similar stories for other groups like, alkalyne earth metals, halogens and noble gases.


You can also tell trends in electroneativities, and atomic radii, for a row of elements, as per the order they are in the row.


So, the current array resulted very helpul for chemists to explain and predict the behavior and properties of the elements.

You might be interested in
When glucose is fermented, ethanol is formed together with ………………….
levacccp [35]

Answer:

carbon dioxide and oxygen

3 0
3 years ago
How many protons does carbons have?
ira [324]
Carbon has 6 protons
4 0
3 years ago
Read 2 more answers
What is the molarity of formaldehyde in a solution containing 0.25 grams of formaldehyde per mL?
Vikentia [17]

Answer:

8.33mol/L

Explanation:

First, let us calculate the molar mass of of formaldehyde (CH2O). This is illustrated below:

Molar Mass of CH2O = 12 + (2x1) + 16 = 12 + 2 + 16 = 30g/mol

Mass of CH2O from the question = 0.25g

Number of mole CH2O =?

Number of mole = Mass /Molar Mass

Number of mole of CH2O = 0.25/30 = 8.33x10^-3mole

Now we can calculate the molarity of formaldehyde (CH2O) as follow:

Number of mole of CH2O = 8.33x10^-3mole

Volume = 1mL

Converting 1mL to L, we have:

1000mL = 1L

Therefore 1mL = 1/1000 = 1x10^-3L

Molarity =?

Molarity = mole /Volume

Molarity = 8.33x10^-3mole/1x10^-3L

Molarity = 8.33mol/L

Therefore, the molarity of formaldehyde (CH2O) is 8.33mol/L

3 0
3 years ago
1. Using the Slater rule, determine the effective nuclear charge of platinum.
AleksandrR [38]

Answer:

Z* = 3.55

Explanation:

Slater rule says that:

Z*= Z - S

Z* be the nuclear effective charge

Z is the nuclear charge

S is the shielding constant

First we write the electronic configuration of platinum:1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 3d^{10} 4s^{2} 4p^{6} 4d^{10} 5s^{2} 5p^{6} 4f^{14} 5d^{9} 6s^{1}

The first Slater rule says that we need to group:

(1s^{2}) (2s, 2p)^{8} (3s, 3p)^{8} (3d^{10}) (4s, 4p)^{8} (4d^{10}) (5s, 5p)^{8} (4f^{14}) (5d^{9}) (6s^{1})

The second rule says that the electrons to the right are not shielding, but we are going to solve the exercise for the last level (6s), so we don't have electrons to the right.

For the third rule we have two considerations, if is ns or np and if is nd or nf:

For our case, we have an electro that is in ns, so the rule says that

-electrons within same group shield 0.35, except the 1s which shield 0.30

-electrons within the n-1 group shield 0.85

-electrons within the n-2 or lower groups shield 1.00

Now we can proceed with the calculation:

The first consideration in the third rule does not apply as we only have one electron on this level.

The second consideration will be as follow for the level 5, where we have 17 electrons.

Finally the third consideration will be for levels 1, 2, 3 and 4, where we have 14 for 4f, 10 for 4d, 8 for 4s and 4p, 10 for 3d, 8 for 3s and 3p, 8 for 2s and 2p and finally 2 for 1s, which gives 60 electrons.

So the result for S=(60*1.00 + 17*0.85) = 74.45

And the equation is: Z* = 78 - 74.45

So Z* = 3.55

3 0
3 years ago
Hello comets~<br>help me with these questions ​
Vadim26 [7]

Impurities of brine solution

  • calcium chloride
  • calcium sulphate
  • magnesium chloride
  • sodium sulphate

Characteristics of halides of beryllium

  • covalent bond
  • does not conduct electricity
  • In organic solvents, it is soluble.

4 0
2 years ago
Read 2 more answers
Other questions:
  • Nolan and Hunter are studying heat flow, so they design the following apparatus. The apparatus consists of two identical glass c
    7·2 answers
  • Is cake an acid base reaction
    13·1 answer
  • Aliphatic compounds are formed from a.animal fats b.plant cellulose c.bonding inorganic compound d.bonding hexane and methane mo
    11·1 answer
  • True or false: properties help us identify matter
    10·2 answers
  • What is the electrical charge of an atom that has lost an electron?
    5·1 answer
  • Pleaseeeeeefgghhbbbbbbbbbb
    8·1 answer
  • Which statement describes an investigation to determine a chemical property? A. determining the reactivity of baking soda and vi
    5·2 answers
  • What 2 elements are in the same group?
    5·2 answers
  • How many liters will 2.76 mol CO2 occupy?<br> 2.76 mol<br> II
    9·1 answer
  • 15. Which sample of argon gas has the same number of atoms as a 100.-milliliter sample of helium gas at 1.0 atm and 300. K? A) 5
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!