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grin007 [14]
2 years ago
14

A box is at rest on an inclined surface. Which diagram correctly illustrates all forces, including any component forces? Assume

the x-axis is parallel to the surface.
Physics
1 answer:
blsea [12.9K]2 years ago
6 0

A box is at rest on an inclined surface. The last diagram correctly illustrates all forces, including any component force, therefore the correct option is D.

<h3>Describe friction?</h3>

When two physical objects' surfaces come into contact, a force called friction acts to hinder or resist the relative motion of the items. Any two surfaces of things cannot simply slide over or across one another due to the friction force. It depends on the amount of force used on the object.

Additionally, there should be no net vertical forces acting on the inclined block. Fv=0

Therefore, the appropriate diagram is D.

Learn more about force on:

brainly.com/question/15624880

#SPJ1

A box is at rest on an inclined surface. Which diagram correctly illustrates all forces, including any component forces?

Assume the x-axis is parallel to the surface.

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174

Explanation:

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A deer is running from a mountain lion when it encounters a fence that is 1.50 m high. Seeing the fence, the deer jumps, leaving
Novosadov [1.4K]

Answer:

Explanation:

Given

Initial Velocity (u)=13 m/s

angle=29^{\circ}

distance between fence and deer=2.5 m

We consider deer jump similar to projectile motion

equation of trajectory

y=xtan\theta -\frac{gx^2}{2u^2(cos\theta )^2}

y=2.5tan(29)-\frac{9.8\times 2.5^2}{2\times 13^2\times (cos29)^2}

y=1.385-0.2368=1.148 m

Thus deer will cross the fence with an difference in its jump and fence

1.5-1.148=0.351 m

h_{max}=\frac{u^2sin^2\theta }{2g}

h_{max}=\frac{13^2\times (sin29)^2}{2\times 9.8}

h_{max}=2.02 m

so deer rises during when it is over fence

8 0
4 years ago
In a circuit, three pieces of wire labeled A, B and C are joined at a common point, D. If wire B carries 1.5 mA in a direction a
Alex_Xolod [135]

Answer:

correct option is a. 0.2 mA toward D

Explanation:

given data

B carries = 1.5 mA

C carries current  = 1.3 mA

solution

we take positive direction of current going away from the point D

and negative direction of current coming towards point D

so we use here kirchoff's current law   that is

iA + iB + iC = 0    ......................1

iA + 1.5 + (-1.3) = 0

iA = - 0.2 mA  

so that current in wire A is 0.2 mA towards point D

correct option is a. 0.2 mA toward D

7 0
3 years ago
For fully developed laminar pipe flow in a circular pipe, the velocity profile is u(r) = 2(1-r2 /R2 ) in m/s, where R is the inn
sdas [7]

Answer:

a) v_{max} = 2\ \textup{m/s}

b) v_{avg} = 1\ \textup{m/s}

c) Q = 1.256 × 10⁻³ m³/s

Explanation:

Given:

The velocity profile as:

u(r) = 2(1-\frac{r^2}{R^2} )

Now, the maximum velocity of the flow is obtained at the center of the pipe

i.e r = 0

thus,

v_{max}=u(0) = 2(1-\frac{0^2}{R^2} )

or

v_{max} = 2\ \textup{m/s}

Now,

v_{avg} = \frac{v_{max}}{2}\ \textup{m/s}

or

v_{avg} = \frac{2}}{2}\ \textup{m/s}

or

v_{avg} = 1\ \textup{m/s}

Now, the flow rate is given as:

Q = Area of cross-section of pipe × v_{avg}

or

Q = \frac{\pi D^2}{4}\times v_{avg}

or

Q = \frac{\pi 0.04^2}{4}\times 1

or

Q = 1.256 × 10⁻³ m³/s

7 0
3 years ago
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