A box is at rest on an inclined surface. Which diagram correctly illustrates all forces, including any component forces? Assume
1 answer:
A box is at rest on an inclined surface. The last diagram correctly illustrates all forces, including any component force, therefore the correct option is D.
<h3>Describe friction?</h3>When two physical objects' surfaces come into contact, a force called friction acts to hinder or resist the relative motion of the items. Any two surfaces of things cannot simply slide over or across one another due to the friction force. It depends on the amount of force used on the object.
Additionally, there should be no net vertical forces acting on the inclined block. Fv=0
Therefore, the appropriate diagram is D.
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A box is at rest on an inclined surface. Which diagram correctly illustrates all forces, including any component forces?
Assume the x-axis is parallel to the surface.
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Answer:
The net displacement of the car is 3 km West
Explanation:
Please see the attached drawing to understand the car's trajectory: First in the East direction for 4 km (indicated by the green arrow that starts at the origin (zero), and stops at position 4 on the right (East).
Then from that position, it moves back towards the West going over its initial path, it goes through the origin and continues for 3 more km completing a moving to the West a total of 7 km. This is indicated in the drawing with an orange trace that end in position 3 to the left (West) of zero.
So, its NET displacement considered from the point of departure (origin at zero) to the final point where the trip ended, is 3 km to the west.
To solve the problem it is necessary to apply conservation of the moment and conservation of energy.
By conservation of the moment we know that
Where
M=Heavier mass
V = Velocity of heavier mass
m = lighter mass
v = velocity of lighter mass
That equation in function of the velocity of heavier mass is
Also we have that
On the other hand we have from law of conservation of energy that
Where,
W_f = Work made by friction
KE = Kinetic Force
Applying this equation in heavier object.
Here we can apply the law of conservation of energy for light mass, then
Replacing the value of
Deleting constants,