1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
grin007 [14]
2 years ago
14

A box is at rest on an inclined surface. Which diagram correctly illustrates all forces, including any component forces? Assume

the x-axis is parallel to the surface.
Physics
1 answer:
blsea [12.9K]2 years ago
6 0

A box is at rest on an inclined surface. The last diagram correctly illustrates all forces, including any component force, therefore the correct option is D.

<h3>Describe friction?</h3>

When two physical objects' surfaces come into contact, a force called friction acts to hinder or resist the relative motion of the items. Any two surfaces of things cannot simply slide over or across one another due to the friction force. It depends on the amount of force used on the object.

Additionally, there should be no net vertical forces acting on the inclined block. Fv=0

Therefore, the appropriate diagram is D.

Learn more about force on:

brainly.com/question/15624880

#SPJ1

A box is at rest on an inclined surface. Which diagram correctly illustrates all forces, including any component forces?

Assume the x-axis is parallel to the surface.

You might be interested in
Which of the following statements best describes energy conservation in heat engines?
Lorico [155]
B is the correct answer
5 0
3 years ago
A car, starting from the origin, travels
sweet [91]

Answer:

The net displacement of the car is 3 km West

Explanation:

Please see the attached drawing to understand the car's trajectory: First in the East direction for 4 km (indicated by the green arrow that starts at the origin (zero), and stops at position 4 on the right (East).

Then from that position, it moves back towards the West going over its initial path, it goes through the origin and continues for 3 more km completing a moving to the West a total of 7 km. This is indicated in the drawing with an orange trace that end in position 3 to the left (West) of zero.

So, its NET displacement considered from the point of departure (origin at zero) to the final point where the trip ended, is 3 km to the west.

8 0
3 years ago
Read 2 more answers
Write a hypothesis for Part II of the lab, which is about the relationship described by F = ma. In the lab, you will use a toy c
hoa [83]

Answer:

F=ma is the relationship where, F is force, m is mass and a is acceleration.

Newton's second law states that  the unbalanced force applied to the object accelerates the object which is directly proportional to the force and inversely to the mass.

If we apply force to a toy car then It will accelerate.

This is how Newton's second law of motion is verified.

5 0
3 years ago
Read 2 more answers
An object at rest on a flat, horizontal surface explodes into two fragments, one seven times as massive as the other. The heavie
leva [86]

To solve the problem it is necessary to apply conservation of the moment and conservation of energy.

By conservation of the moment we know that

MV=mv

Where

M=Heavier mass

V = Velocity of heavier mass

m = lighter mass

v = velocity of lighter mass

That equation in function of the velocity of heavier mass is

V = \frac{mv}{M}

Also we have that m/M = 1/7 times

On the other hand we have from law of conservation of energy that

W_f = KE

Where,

W_f = Work made by friction

KE = Kinetic Force

Applying this equation in heavier object.

F_f*S = \frac{1}{2}MV^2

\mu M*g*S = \frac{1}{2}MV^2

\mu g*S = \frac{1}{2}( \frac{mv}{M})^2

\mu = \frac{1}{2} (\frac{1}{7}v)^2

\mu = \frac{1}{98}v^2

\mu = \frac{1}{g(98)(5.1)}v^2

Here we can apply the law of conservation of energy for light mass, then

\mu mgs = \frac{1}{2} mv^2

Replacing the value of \mu

\frac{1}{g(98)(5.1)}v^2  mgs = \frac{1}{2}mv^2

Deleting constants,

s= \frac{(98*5.1)}{2}

s = 249.9m

7 0
4 years ago
According to the graph above, how large of a force is needed in order to stretch the string 1.00 meters?
gulaghasi [49]

My guess for this one would be; 400 N

My reasoning would be; it starts at 0 on both X and Y, if you need to get to 1.00 meters thats 4/4. 1/4 of 1.00 is .25, and on .25 its on 100 so multiply it by 4 to make 1.00 and you get 400 N

7 0
3 years ago
Read 2 more answers
Other questions:
  • A pendulum consists of a 1.7-kg block hanging on a 1.6-m length string. A 0.01-kg bullet moving with a horizontal velocity of 82
    14·1 answer
  • One piece of copper jewelry at 111°C has exactly twice the mass of another piece, which is at 28°C. Both pieces are placed insid
    5·1 answer
  • List three ways the earth is different today from when it was first formed
    5·2 answers
  • What is the bone in your arm
    14·2 answers
  • A large truck is moving at 22.0 m/s. If its momentum is 125,000 kg • , what is the truck's mass?
    12·2 answers
  • Thomas is climbing Mt. Everest. What happens as he climbs farther up the mountain?
    15·2 answers
  • Every year, new records in track and field events are recorded. Let's take a historic look back at some exciting races.
    11·2 answers
  • Which organ system do you think is the most interesting? Why?
    5·1 answer
  • Sports managers have the potential to earn more than a million dollars per year.<br> True<br> false
    9·1 answer
  • In what ways is thermal energy transferred during physical and chemical changes
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!