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4 years ago

What qualities did Galilea, Sir Isaac Newton, and Albert Einstein have?

1 answer:

4 0

The qualities that Galileo , Sir Isaac Newton, and Albert Einstein is that they all created models of nature. Galileo discovered Jupiter's four moons and declared that the earth revolves around the sun.Newton developed the three laws of motion, which formed the basic principles of modern physics.Albert Einstein discovered the general theory of relativity, but best known for his mass-energy equivalence formula E=mc².

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A flat coil of wire consisting of 20 turns, each with an area of 50 cm2, is positioned perpendicularly to a uniform magnetic fie

jenyasd209 [6]

Answer:

0.5 A

Explanation:

N = 20, A = 50 cm^2 = 50 x 10^-4 m^2, dB = 6 - 2 = 4 T, dt = 2 s, R = 0.4 ohm

The induced emf is given by

e = - N dФ/dt

Where, dФ/dt is the rate of change of magnetic flux.

Ф = B A

dФ/dt = A dB/dt

so,

e = 20 x 50 x 10^-4 x 4 / 2 = 0.2 V

negative sign shows the direction of magnetic field.

induced current, i = induced emf / resistance = 0.2 / 0.4 = 0.5 A

5 0

3 years ago

ANSWER ASAP

vodka [1.7K]

B the desert was once covered in water

3 0

3 years ago

Read 2 more answers

AP Physics I, shouldn't be too hard.

Nana76 [90]

Answer:

The correct option is;

D. The kinetic energy decreases by 3·m₀·v₀²

Explanation:

The given parameters are;

The mass of object X = m₀

The initial velocity of object X = v₀

The mass of object Y = 2·m₀

The initial velocity of object Y = -2·v₀

By conservation of linear momentum, we have;

The total initial momentum = The total final momentum

Therefore, we have;

The total initial momentum = m₀·v₀ - 2·m₀·2·v₀ = The total final momentum

∴ The total final momentum = -3·m₀·v₀

The total mass of the two object after sticking together = 2·m₀ + m₀ = 3·m₀

Therefore, the velocity of the two objects after collision = (The total final momentum)/(Total mass) = -3·m₀·v₀/(3·m₀) = -v₀

The kinetic energy = 1/2 × Mass × (Velocity)²

Therefore, the kinetic energy after collision = 1/2 × (3·m₀) × v₀² = 3·m₀·v₀²/2

The kinetic energy before collision = 1/2 × m₀ × v₀² + 1/2 × (2·m₀) × (2·v₀)² = (1/2 + 4) × (m₀·v₀²)

∴ The kinetic energy before collision = 9·(m₀·v₀²)/2

The change in kinetic energy = The kinetic energy after collision - The kinetic energy before collision = 3·m₀·v₀²/2 - 9·(m₀·v₀²)/2 = -3·m₀·v₀²

Therefore, the kinetic energy decreases by 3·m₀·v₀².

5 0

3 years ago

In a simple hydraulic press, similar to the brakes in your car, the system works on the principle that

Alex

<span>B) equal pressures are applied from your foot to the pedal to the brake pads.
That would be the answer.

Hope this helps!</span>

3 0

3 years ago

Read 2 more answers

Consider two oppositely charged, parallel metal plates. The plates are square with sides L and carry charges Q and -Q. What is t

antoniya [11.8K]

Answer:

E = $\frac{Q}{L^2 \epsilon_o}$

Explanation:

For this exercise we use that the electric field is a vector, so the resulting field is

E_total = E₁ + E₂ (1)

since the field has the same direction in the space between the planes

Let's use Gauss's law for the electric field of each plate

Let's use a Gaussian surface that is a cylinder with the base parallel to the plate, therefore the normal to the surface and the field lines are parallel and the angle is zero so cos 0 = 1

Ф = ∫ .dA = $q_{int}$ /ε₀

if we assume that the charge is uniformly distributed on the plate we can define a charge density

σ = q_{int} A

as the field exists on both sides of the plate on the inside

E A = A σ / 2ε₀

E = σ / 2ε₀

we substitute in equation 1

E = σ /ε₀

for the complete plate

σ = Q / A = Q / L²

we substitute

E = $\frac{Q}{L^2 \epsilon_o}$

7 0

3 years ago