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3 years ago

Is the following relation a function?

Mathematics

2 answers:

astra-53 [7]3 years ago

8 0

Answer:

yes!!!

Step-by-step explanation:

Short explanation. The same y value can be true for many "exs". But the same x value can only have ONE y value to define a function. So if you draw y = 0.5 across that graph that you have given us, you get many x values that have 0.5 as a y value.

If on the other hand, you draw a line of x = 1, there is only 1 value that y has and that is zero.

This is a function.

Pavel [41]3 years ago

7 0

Yes, I think so I'm sorry if I'm wrong

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Elena-2011 [213]

16 because 2•0 is 0. 8-0 is 8 and 2(8) is 16

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3 years ago

If f(x)=x/2-2 and g(x)=2x^2+x-3, find (f+g)(x)

Lelu [443]

Hello :
If f(x)=x/2-2 and g(x)=2x^2+x-3, find (f+g)(x)
(f+g)(x)= f(x) +g(x) = x/2-2 +2x²+x-3 = x/2 +2x²+x-5
(f+g)(x)= (x+4x²-2x-10) /2
(f+g)(x)= (4x²+3x-10)/2 = 2x²+3/2 x -5

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3 years ago

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guapka [62]

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3 years ago

The probability that your call to a service line is answered in less than 30 seconds is 0.75. Assume that your calls are indepen

vfiekz [6]

Answer:

a) 0.2581

b) 0.4148

c) 17

Step-by-step explanation:

For each call, there are only two possible outcomes. Either they are answered in less than 30 seconds. Or they are not. The probabilities for each call are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$p = 0.75$

a. If you call 12 times, what is the probability that exactly 9 of your calls are answered within 30 seconds? Round your answer to four decimal places (e.g. 98.7654).

This is $P(X = 9)$ when $n = 12$ . So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 9) = C_{12,9}.(0.75)^{9}.(0.25)^{3} = 0.2581$

b. If you call 20 times, what is the probability that at least 16 calls are answered in less than 30 seconds? Round your answer to four decimal places (e.g. 98.7654).

This is $P(X \geq 16)$ when $n = 20$