Given Equations :
✿ 2x + y = 20 ------------------ [1]
✿ 6x - 5y = 12 ----------------- [2]
Multiplying Equation [1] with 5, We get :
⇒ 5(2x + y) = 5(20)
⇒ 10x + 5y = 100 -------------- [3]
Adding Equations [2] and [3], We get :
⇒ (10x + 5y) + (6x - 5y) = 100 + 12
⇒ 16x = 112
⇒ x = 7
Substituting x = 7 in Equation [1], We get :
⇒ 2(7) + y = 20
⇒ 14 + y = 20
⇒ y = 20 - 14
⇒ y = 7
So, The Solution for the Given System of Equations is : (x , y) = (7 , 7)
T = 40000 + 40000(1.03) + 40000(1.03)^2 + ... + 40000(1.03)^15
Multiply the above equation by 1.03 giving
1.03(T) = 40000(1.03) + 40000(1.03)^2 + 40000(1.03)^3 + ... + 40000(1.03)^15 + 40000(1.03)^16
Now subtract the first equation from the second to give
0.03T = 40000(1.03)^16 - 40000
0.03T = 40000(1.03^16 - 1)
0.03T = 24188.26
T = 24188.26 / 0.03 = $806275.25
Answer:
Step-by-step explanation:
Mean: sum of terms/ number of terms
4 + 2 + 3 + 1 + 1 + 5 = 16
Numbr of terms = 6
16/6 = 2.66
Answered by g a u t h m a th
Is the goal to simplify? You just need to multiply the exponents for each factor:
(2z^2)^(-3)
= 2^(-3) x z^(2 x -3)
= (1/2)^3 x z^(-6)
= (1/8) x (1/z)^6
= 1/(8z^6)
Answer:
Option (D).
Step-by-step explanation:
If the graph of a relation has two output values for a single input value, relation will not be considered to be a function.
Option (A).
For the input values of x = -1, there are two output values, y = -1, 1.
Therefore, given relation is not a function.
Option (B).
Since, all the parabolas don't represent a function, given parabola in the graph is not a function.
Option (C).
Not a function. It's a relation.
Option (D).
Line plotted in the graph has a distinct output value for every input value.
Therefore, the given graph represents a linear function.
