PE= 3kg x 10N/kg x 10m
= 300J
Answer:
Explanation:
Horizontal displacement
x = 120 t
Vertical position
y = 3610 - 4.9 t²
y = 0 for the ground
0 = 3610 - 4.9 t²
t = 27.14 s
This is the time it will take to reach the ground .
During this period , horizontal displacement
x = 120 x 27.14 m
= 3256.8 m
So packet should be released 3256.8 m before the target.
Getting a good night sleep can benefit you in a lot of ways. Also that’s not a question.
At the end of the laps, the runner's displacement is zero.
Answer:
the answer will be 24.40 ohms law
Explanation:
