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MA_775_DIABLO [31]
1 year ago
10

The ratio between the modulating signal voltage and the carrier voltage is called?.

Engineering
1 answer:
gregori [183]1 year ago
3 0

The ratio between the modulating signal voltage and the carrier voltage is called the Modulation index.

<h3>What are the modulation index and its formula?</h3>

The carrier voltage and the voltage of the modulating signal (Vm) are multiplied to create the modulation index (Vc). The modulation index equation is given below. m = Vm/Vc.

The modulation index should be represented by an integer between 0 and 1. When m exceeds 1, the modulated waveform exhibits severe distortion.

It is the peak to peak ratio of the carrier wave to the modulating signal. μ = Am/Ac. It indicates the level of distortion or noise. Reduced transmitted signal distortion is correlated with a lower modulation index value.

The modulation index is calculated by comparing the line-to-neutral inverter output voltage's fundamental component amplitude to one-half of the available DC bus voltage.

To learn more about modulation index refer to:

brainly.com/question/24001284

#SPJ4

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Why did you choose agricultural and biosystem as a course? Help me guys
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2 years ago
The size of Carvins Cove water reservoir is 3.2 billion gallons. Approximately, 11 cfs of water is continuous withdrawn from thi
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Answer:

471 days

Explanation:

Capacity of Carvins Cove water reservoir = 3.2 billion gallons i.e. 3.2 x 10˄9 gallons

As,  

1 gallon = 0.133 cubic feet (cf)

Therefore,  

Capacity of Carvins Cove water reservoir in cf  = 3.2 x 10˄9 x 0.133

                                                                         = 4.28 x 10˄8

 

Applying Mass balance i.e

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Here  

Mass In = 0.5 cfs

Mass out = 11 cfs

Putting values in (Eq. 01)

Accumulation  = 0.5 - 11

                         = - 10.5 cfs

 

Negative accumulation shows that reservoir is depleting i.e. at a rate of 10.5 cubic feet per second.

Converting depletion of reservoir in cubic feet per hour = 10.5 x 3600

                                                                                       = 37,800

 

Converting depletion of reservoir in cubic feet per day = 37, 800 x 24

                                                                                         = 907,200  

 

i.e. 907,200 cubic feet volume is being depleted in days = 1 day

1 cubic feet volume is being depleted in days = 1/907,200 day

4.28 x 10˄8 cubic feet volume will deplete in days  = (4.28 x 10˄8) x                    1/907,200

                                                                                 = 471 Days.

 

Hence in case of continuous drought reservoir will last for 471 days before dry-up.

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