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MA_775_DIABLO [31]
1 year ago
10

The ratio between the modulating signal voltage and the carrier voltage is called?.

Engineering
1 answer:
gregori [183]1 year ago
3 0

The ratio between the modulating signal voltage and the carrier voltage is called the Modulation index.

<h3>What are the modulation index and its formula?</h3>

The carrier voltage and the voltage of the modulating signal (Vm) are multiplied to create the modulation index (Vc). The modulation index equation is given below. m = Vm/Vc.

The modulation index should be represented by an integer between 0 and 1. When m exceeds 1, the modulated waveform exhibits severe distortion.

It is the peak to peak ratio of the carrier wave to the modulating signal. μ = Am/Ac. It indicates the level of distortion or noise. Reduced transmitted signal distortion is correlated with a lower modulation index value.

The modulation index is calculated by comparing the line-to-neutral inverter output voltage's fundamental component amplitude to one-half of the available DC bus voltage.

To learn more about modulation index refer to:

brainly.com/question/24001284

#SPJ4

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4) designing the model and drawing conclusions​

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Explanation:

Based on the flowchart, a model improvement process involves the implementation of a process or model improvement cycle such as the Plan Do Study Act, PDSA cycle, however feedback to the process will be be gotten from testing the model and analyzing the results of the tests. When grey areas or aspects of the model are found that cause the system to malfunction are determined, steps should then be taken to improve the performance of the model.

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1. Looking at the case study provided under the Companion Material section, what is the main problem that is addressed in this c
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Explanation:

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Answer:

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(b) The entropy change of the mixture is 1066.0279 J/K

Explanation:

Here we have

Molar mass of H₂ = 2.01588 g/mol

Molar mass of N₂ = 28.0134 g/mol

Number of moles of H₂ = 500/2.01588  = 248 moles

Number of moles of N₂ = 1200/28.0134 = 42.8 moles

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V₁ = n·R·T/P = 290.8×8.3145×300/100000 = 7.25 m³

Since the volume is doubled then

V₂ = 2 × 7.25 = 14.51 m³

At constant pressure, the temperature is doubled, therefore

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If we assume constant specific heat at the average temperature, we have

Heat supplied = m₁×cp₁×dT₁ + m₂×cp₂×dT₂

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b)  \Delta S = - R(n_A \times lnx_A + n_B \times ln x_B)

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Therefore, x_A = 248 /(248 + 42.8) = 0.83

x_B = 42.8/(248 + 42.8) = 0.1472

∴ \Delta S = - 8.3145(248 \times ln0.83 + 42.8 \times ln 0.1472) =  1066.0279 J/K

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