13.6 mol of CuCl2
you wanna use the factor label
A metric unit for 1,000 grams, or for measuring weight!
<span><span>N2</span><span>O5</span></span>
Explanation!
When given %, assume you have 100 g of the substance. Find moles, divide by lowest count. In this case you'll end up with
<span><span>25.92 g N<span>14.01 g N/mol N</span></span>=1.850 mol N</span>
<span><span>74.07 g O<span>16.00 g O/mol O</span></span>=4.629 mol O</span>
The ratio between these is <span>2.502 mol O/mol N</span>, which corresponds closely with <span><span>N2</span><span>O5</span></span>.
Hello!! Your answer would be 3.33x10^-10. Since you are trying to find one place holder for the notation, you will move your decimal 10 times to the right for it to be in scientific notation. Always remember that for scientific notation, you must have one whole number in front of a decimal at all times. After you put the decimal after the first whole number, count how many times you have moved your decimal. If you have a lot of zeros in front of your numbers, you will always have a negative exponent, and if you have a negative exponent, then you will have a lot of zeros. If you have a whole number exponent, it will be up in the 100s, 1000s, or 10000s, something like that. It will have a high value with a higher exponent. I hope I helped!! If you have any more questions then do not hesitate to message me and let me know. Have a great day!! :)
First, we need to get no.of moles of acetic acid = molarity * volume
= 0.3 m * 0.5 L
= 0.15 moles
then, we need to get no. of moles acetate = molarity *volume
= 0.2m * 0.5L
= 0.1 moles
and we have also to get moles of NaOH = molarity * volume
= 1 m* 0.02L
= 0.02 moles
according to the reaction equation and by using ICE table:
CH3COOH + OH- → CH3COO- + H2O
∴ moles acetic acid = 0.15 - 0.02 = 0.13 moles
when [acetic acid] = moles / total volume
= 0.13 moles / (0.5L + 0.02L)
= 0.25 M
and moles of acetate = 0.1 + 0.02 = 0.12 moles
∴[acetate] = moles / total volume
= 0.12 moles / 0.52L
= 0.23 M
and when we have the value of Ka so we can get the Pka from this formula:
Pka = -㏒ Ka
= -㏒ 1.8 x 10^-5
= 4.7
by using H-H equation we can get the PH:
∵PH = Pka + ㏒[acetate] /[acetic acid]
∴PH = 4.7 + ㏒(0.23 /0.25]
= 4.66