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Natalija [7]
2 years ago
12

A flask is filled with 1.57 L (L: liter) of a liquid at 90.6 °C. When the liquid is cooled to 10.2 °C, its volume is only 1.38 L

. however. Neglect the contraction of the flask. What is the coefficient of volume expansion of the liquid?
Physics
1 answer:
nydimaria [60]2 years ago
8 0

The coefficient of volume expansion of the liquid = 1.97 × 10⁻³ /⁰C

<h3>What is the coefficient of volume expansion of the liquid?</h3>

The amount of volume that a substance expands by per unit of its original volume for each degree that its temperature rises is known as the coefficient of volume expansion.

As we know, The coefficient of volume expansion of the liquid

= change in volume/(original volume × temperature difference)

= (V₂ - V₁)/[V₁ × (T₂ - T₁)]

Change in volume = (V₂ - V₁)

Here, V₂ ( final volume) = 1.31 L

V₁  (initial volume)= 1.55 L

T₂ (final temperature) = 14.7 degrees

T₁ (initial temperature) = 96 degrees

The coefficient of volume expansion of the liquid

= (1.31 - 1.55) / [1.5 × (14.7- 96)]

= 1.97 × 10⁻³ /⁰C

Thus, the coefficient of volume expansion of the liquid = 1.97 × 10⁻³ /⁰C

To know more about coefficient of volume expansion refer to:

brainly.com/question/24042303

#SPJ1

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A vertical spring with stiffness k originally is at rest with no mass attached. Then, a mass M is attached, and the spring rocks
Alina [70]

Answer:

The position of the spring in terms of g, m & k is x = \frac{m g}{k}

Explanation:

Stiffness of the spring = k

Mass = m

When a mass m is attached with the spring then spring stretched. in that case the force exerted on the spring is equal to weight of the mass attached.

⇒ Force exerted on the spring F = k x

⇒ m g = k x

⇒ x = \frac{m g}{k}

This is the position of the spring in terms of g, m & k.

8 0
4 years ago
When the electron in a hydrogen atom moves from n = 6 to n = 1, light with a wavelength of ________ nm is emitted?
Oduvanchick [21]
First we find the energy level with the following formula, where a is the energy level, n1 is the final energy level, n2 is the starting energy level and r is Rydberg's constant in Joules
a = r \times ( \frac{1}{n1}  -  \frac{1}{n2} )
We insert the values

a = 2.18 \times  {10}^{ - 18}  \times ( \frac{1}{ {1}^{2} } -  \frac{1}{ {6}^{2} }  )
= 2.12 \times {10}^{ - 18}
The wavelength is found with this formula, where h is Planck's constant and c is the speed of light
wavelength =  \frac{h \times c}{a}
Finally we insert the values
\frac{6.626 \times  {10}^{ - 34}  \times 3 \times  {10}^{8} }{2.12 \times  {10}^{ - 18} }  = 9.376 \times  {10}^{ - 8}
Which is the same as 93.8 nm
3 0
3 years ago
Một chất điểm khối lượng m=200g chuyển
MrMuchimi
Can you please translate to English?
8 0
2 years ago
A pitcher throws a baseball that reaches the catcher in 0.75 s. The ball curves because it is spinning at an average angular vel
7nadin3 [17]

The change in angular displacement as a function of time is the definition given for angular velocity, this is mathematically described as

\omega = \frac{\theta}{t}

Here,

\theta = Angular displacement

t = time

The angular velocity is given as

\omega = 230rev/min

PART A) The angular velocity in SI Units will be,

\omega = 230rev/min (\frac{1min}{60s})(\frac{2\pi rad}{1rev})

\omega = \frac{23}{3}\pi rad/s \approx 24.08rad/s

PART B) From our first equation we can rearrange to find the angular displacement then

\theta = \omega t

Replacing,

\theta = (24.08)(0.75)

\theta = 18.06 rad

4 0
3 years ago
A freight car with a mass of 10 metric tons is rolling at 108 km/h along a level track when it collides with another freight car
Rufina [12.5K]

Answer:

20 metric tons

Explanation:

Using the Principle of Conservation of Linear Momentum which states that the total momentum of a system is constant in any direction in which no external force acts.

momentum before collision= momentum after collision

mathematically expressed as

m1u1 + m2u2 = m1v1+m2v2 =0

where:

m1= mass of rolling freight car = 10 metric tons = 10Mg

1 ton = 1000kg= 1Mg

u1 =initial velocity of freight car = 108km/h,

m2 = mass of stationary freight car = ?, this the unknown we are finding

u2 = initial velocity of

m2 = 0, because it is at rest,

v1= final velocity of m1,

v2= final velocity of m2

since they move together in the same direction they share a common final velocity as such

v1=v2= 36km/h

substituting valves in expression give

m1u1 + m2u2 = m1v1 + m2v2= 0

10Mgx 108km/hr + m2 x 0 = 10Mg x 36km/h + m2x36km/h

1080( Mg x km/hr) + 0 = 360 (Mg x Km/h) + 36m2 (km/h)

1080 (Mgx km/hr) - 360(Mg x km/h) = 36m2 (km/h)

720(Mg x km/h) = 36m2 (km/h)

divide both side by  36 (km/h) gives

m2 = 20Mg =20 metric tons

3 0
4 years ago
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