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balu736 [363]
3 years ago
11

How would the absence of gravity affect the formation of planets?

Physics
2 answers:
Mumz [18]3 years ago
3 0
In the absence of gravity, t<span>he rocks and debris
would never accrete into a planet. (B)

Also by the way, it wouldn't matter much, because
there wouldn't be a star to orbit around, AND orbits
wouldn't exist either.</span>
11111nata11111 [884]3 years ago
3 0

Answer:

(B)The rocks and debris would never accrete into a planet.

Explanation:

During the formation of planets, rocks and debris aggregate together because of the gravity. Gravity, in fact, is the force exerted between every object that has mass. The magnitude of the force of gravity is given by

F=G\frac{m_1 m_2}{r^2}

where

G is the gravitational constant

m1 and m2 are the masses of the two particles

r is the distance between the two particles

Without the force of gravity, there will be no force that would accrete the rocks and the debris into a planet.


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I think the answer is 4) All of the above!! :)
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3 years ago
A simple pendulum has a period of 3.45 second, when the length of the pendulum is shortened by 1.0m, the period is 2.81 second c
den301095 [7]

Answer:

Original length = 2.97 m

Explanation:

Let the original length of the pendulum be 'L' m

Given:

Acceleration due to gravity (g) = 9.8 m/s²

Original time period of the pendulum (T) = 3.45 s

Now, the length is shortened by 1.0 m. So, the new length is 1 m less than the original length.

New length of the pendulum is, L_1=L-1

New time period of the pendulum is, T_1=2.81\ s

We know that, the time period of a simple pendulum of length 'L' is given as:

T=2\pi\sqrt{\frac{L}{g}}-------------- (1)

So, for the new length, the time period is given as:

T_1=2\pi\sqrt{\frac{L_1}{g}}------------ (2)

Squaring both the equations and then dividing them, we get:

\dfrac{T^2}{T_1^2}=\dfrac{(2\pi)^2\frac{L}{g}}{(2\pi)^2\frac{L_1}{g}}\\\\\\\dfrac{T^2}{T_1^2}=\dfrac{L}{L_1}\\\\\\L=\dfrac{T^2}{T_1^2}\times L_1

Now, plug in the given values and calculate 'L'. This gives,

L=\frac{3.45^2}{2.81^2}\times (L-1)\\\\L=1.507L-1.507\\\\L-1.507L=-1.507\\\\-0.507L=-1.507\\\\L=\frac{-1.507}{-0.507}=2.97\ m

Therefore, the original length of the simple pendulum is 2.97 m

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2 years ago
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Answer:

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Explanation:

5 0
2 years ago
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Answer:

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Answer:

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