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balu736 [363]
4 years ago
11

How would the absence of gravity affect the formation of planets?

Physics
2 answers:
Mumz [18]4 years ago
3 0
In the absence of gravity, t<span>he rocks and debris
would never accrete into a planet. (B)

Also by the way, it wouldn't matter much, because
there wouldn't be a star to orbit around, AND orbits
wouldn't exist either.</span>
11111nata11111 [884]4 years ago
3 0

Answer:

(B)The rocks and debris would never accrete into a planet.

Explanation:

During the formation of planets, rocks and debris aggregate together because of the gravity. Gravity, in fact, is the force exerted between every object that has mass. The magnitude of the force of gravity is given by

F=G\frac{m_1 m_2}{r^2}

where

G is the gravitational constant

m1 and m2 are the masses of the two particles

r is the distance between the two particles

Without the force of gravity, there will be no force that would accrete the rocks and the debris into a planet.


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Two students are watching a person riding a skateboard up and down a ramp. Each student shares what they think about the energy
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Answer:

Explanation:

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Therefore, Raymond is thinking in a right way.

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An electric heater used to boil small amounts of water consists of a 15-Ω coil that is immersed directly in the water. It operat
Allisa [31]

Answer:

t = 1120 seconds

Explanation:

Law of Conservation of Energy: It states that energy can neither be created or destroyed but it can be transformed from one form to another

The heater converts electric energy to heat energy.

According to the law of conservation of Energy,

Heat supplied by the heater = heat gained by the water.

Heat supplied by the heater = (V²/R)t, Where V = voltage, R = Resistance, t = Time.

Heat gained by the water = cm(θ₂ -θ₁)

Where c = specific heat capacity of water, m = mass of water, θ₂= final temperature of water, θ₁= initial temperature of water.

∴ (V²/R)t =  cm(θ₂ -θ₁)

Making  t the subject of the equation,

t =  cm(θ₂ -θ₁) ×R/V²

Where c= 4200 Jkg/K, m=0.80 kg, R = 15 Ω, V = 60 V, θ₁= 20°C, θ₂ = the normal boiling point of water = 100°C

∴ t = (4200×0.8)(100 -20)×15/60²

t = (3360×80×15)/3600

t = 4032000/3600 = 1120 seconds

∴  The time required by the heater to raise the temperature of water to normal boiling point is 1120 seconds.

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When it’s about to be dropped
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