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andriy [413]
10 months ago
15

If 6. 000 g of sugar is mixed with 9. 000 g of water, what is the concentration in weight percent?.

Chemistry
1 answer:
lbvjy [14]10 months ago
7 0

The concentration in weight percent when 6 g of sugar is mixed with 9 g of water is 40%.

There are several ways to denote the concentration of a solution like

  • Molarity
  • Molality
  • Mass percent
  • Mole Fraction

The formula for calculating mass percent is as follows

Mass per cent = (Mass of solute/Mass of solute + Mass of solvent) x 100%

In the given situation sugar is the solute and water is the solvent.

Putting the given values in the above formula

Mass per cent = (6/6+9) x 100%= 6/15 x 100% = 40%

Hence, the concentration in weight percent when 6 g of sugar is mixed with 9 g of water is 40%.

To know more about "concentration of a solution", refer to the link given below:

brainly.com/question/26579666?referrer=searchResults

#SPJ4

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A 5.325g sample of methyl benzoate, a compound in perfumes , was found to contain 3.758 g of carbon, 0.316 g of hydrogen, and 1.
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<u>Answer:</u> The empirical and molecular formula of the compound is C_4H_4O and C_8H_8O_2 respectively

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To formulate the empirical formula, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{3.758g}{12g/mole}=0.313moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.316g}{1g/mole}=0.316moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{1.251g}{16g/mole}=0.078moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.078 moles.

For Carbon = \frac{0.313}{0.078}=4.01\approx 4

For Hydrogen  = \frac{0.316}{0.078}=4.05\approx 4

For Oxygen  = \frac{0.078}{0.078}=1

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : H : O = 4 : 4 : 1

The empirical formula for the given compound is C_4H_4O

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is:

n=\frac{\text{Molecular mass}}{\text{Empirical mass}}

We are given:

Mass of molecular formula = 130 g/mol

Mass of empirical formula = 68 g/mol

Putting values in above equation, we get:

n=\frac{130g/mol}{68g/mol}=1.9\approx 2

Multiplying this valency by the subscript of every element of empirical formula, we get:

C_{(2\times 4)}H_{(2\times 4)}O_{(2\times 2)}=C_8H_8O_2

Hence, the empirical and molecular formula of the compound is C_4H_4O and C_8H_8O_2 respectively

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