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andriy [413]
1 year ago
15

If 6. 000 g of sugar is mixed with 9. 000 g of water, what is the concentration in weight percent?.

Chemistry
1 answer:
lbvjy [14]1 year ago
7 0

The concentration in weight percent when 6 g of sugar is mixed with 9 g of water is 40%.

There are several ways to denote the concentration of a solution like

  • Molarity
  • Molality
  • Mass percent
  • Mole Fraction

The formula for calculating mass percent is as follows

Mass per cent = (Mass of solute/Mass of solute + Mass of solvent) x 100%

In the given situation sugar is the solute and water is the solvent.

Putting the given values in the above formula

Mass per cent = (6/6+9) x 100%= 6/15 x 100% = 40%

Hence, the concentration in weight percent when 6 g of sugar is mixed with 9 g of water is 40%.

To know more about "concentration of a solution", refer to the link given below:

brainly.com/question/26579666?referrer=searchResults

#SPJ4

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\qquad ☀️\pink{\bf{ {Answer  = \: \:   85.57g }}}

Molar mass of \bf Cu_2O

\qquad \twoheadrightarrow\sf 63.546 \times 2 +16

\qquad \pink{\twoheadrightarrow\bf 143.092 g}

<u>As we know</u>–

1 mol =\bf 6.02×10^{23} formula units

1 mol\bf Cu_2O = 143.092 g = \bf 6.02×10^{23}formula units

Henceforth –

\bf 3.60×10^{23} formula units \bf Cu_2O–

\qquad \sf :\implies \dfrac{143.092 \times3.60×10^{23  }}{6.02×10^{23}}

\qquad \sf :\implies \dfrac{143.092 \times3.60×\cancel{10^{23  }}}{6.02×\cancel{10^{23}}}

\qquad \pink{:\implies\bf 85.57 g}

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Explanation:

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3 years ago
Write the ionization equation for hypochlorous acid, HClO, dissolved in water.
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Answer:

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Explanation:

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This is a weak acid that can be dissociated as this:

HClO (l)  →  H⁺ (aq)    +       ClO⁻ (aq)

                 proton   and    hypochlorite.

It is a weak acid, so it can adopt a Ka for its equilibrium

HClO +  H₂O  ⇄   H₃O⁺   +  ClO⁻          Ka

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Explanation:

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