Answer:
1.76m/s²
Explanation:
Given parameters:
Initial velocity = 0m/s
Final velocity = 65m/s
Distance traveled = 1200m
Unknown:
Acceleration = ?
Solution:
This is linear velocity and we apply the appropriate motion equation to solve this problem.
V² = U² + 2as
S is the distance
u is the initial velocity
V is the final velocity
a is the acceleration
Now, insert the parameters and solve;
65² = 0² + 2 x a x 1200
4225 = 2400a
a = 1.76m/s²
A. altitude should be correct
Answer: 5.31 meters
Explanation: Use conservation of energy. Initial energy equals final energy. Initially, there is only kinetic energy (because height = 0 initially). At the end, kinetic energy equals 0 because at max height, there is max potential energy and the ball stops moving for a split second.
mgh = .5mv^2
Masses cancel out
gh = .5v^2
(9.8)(h) = .5(10.2^2)
Solve for h. h = 5.31 meters
The first thing you should know to answer this question is the following conversion:
1mi = 5280feet
We have then that the speed is:
v = ((1/4) * (5280)) / (8.96)
v = 147.32 feet / s
Answer:
the car's velocity (in ft / s) at the finish line is 147.32 feet / s
