Answer:
Explanation:
As the size of the halogen increases their acidity increases. Though HF being a weak acid is a stronger acid than water. H-NH2 is a base, while H-CH3 can be made to produce H+.
For the number less than 0.1 such as 0.006, the zeroes to the right of the decimal point but before the first non zero digit show the decimal place of the first significant digit.
- The number that is given as digits is established using significant figures.
- Any two non-zero digits that are separated by a zero are significant figure.
- Every zero that is both to the right and left of a non-zero digit and the decimal point is not significant figure.
- The quantity of significant figures frequently reveals the degree of measurement accuracy. From the first non-zero digits in the figure, we may determine the number of significant figures.
There is only one significant figure in the provided number 0.06. The decimal place of the first digit is indicated by the zeros that appear to the right of the decimal point but before the first non-zero digit.
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Molecular weight of m is 40g. Hence, name of element m is Calcium. which is represented by the symbol Ca.
Given,
Moles of metal M = 0.300 moles
weight of mF₂ formed =23.4g
we have to find the name of element m...
Now,
m + F₂ → mF₂
1 mole of m reacts with 1 mole of F₂ (or 2 molecule of flourine) to form 1 mole of mF₂
Hence,
0.300 moles of m reacts with 0.300 moles of F₂ to form 0.300 moles of mF₂.
Hence,
23.4 g = 0.300 moles of mf2
0.300 × 38g + 0.300 × m = 23.4 g
Hence
m = 40 g
So, molecular weight of m is 40g. Hence, name of element m is Calcium. which is represented by the symbol Ca.
Thus, from the above conclusion we can say that, name of element m is Calcium. which is represented by the symbol Ca.
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<u>Given:</u>
MilliMoles of N2 = 2.5 mmol = 0.0025 moles
Initial volume V1 = 42 cm3
Final volume V2 = 600 cm3
Temperature T = 300 K
<u>To determine:</u>
The change in Gibbs free energy, ΔG
<u>Explanation:</u>
The change in Gibbs free energy is related to the ration of the volumes:
ΔG = -nRTln(V2)/(V1)
= -0.0025*8.314*300*ln(600/42) = -16.582 J/mol
Ans: The Gibbs free energy for the process is 0.0166 kJ/mol
