Question

when a body moves in a simple harmonic motion, its acceleration at the ends of its path is: group of answer choices zero less than at equilibrium more than g maximum

Answer 1

When a body moves in a simple harmonic motion, its acceleration at the end of its path is more than that of the acceleration at equilibrium.

The acceleration of the body moving in Simple Harmonic Motion(SHM) is given by,

Acceleration = ω^2 A

Here w is the angular velocity of the body and A is the amplitude.

A is the maximum distance of the body from the equilibrium position.

When the body is at an equilibrium position, its amplitude is equal to zero.

Hence, acceleration = ω^2 x 0 = 0

When the body is at the end of its path, its amplitude is equal to A.

Hence, acceleration = ω^2 x A

Therefore,

when a body moves in a simple harmonic motion, its acceleration at the end of its path is more than that of the acceleration at equilibrium.

To know more about "Simple Harmonic Motion", refer to the following link:

brainly.com/question/20885248?referrer=searchResults

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