Answer:
The intensity of light be maximum is for angles 23.3° and 52.3°.
Explanation:
Given that,
Wave length = 632.8 nm
Distance = 1.60 μm
We need to calculate the intensity of light be maximum
Using Bragg's law
We need to calculate the angle for different value of n
Using Bragg's law
For n₁,
Put the value into the formula
For n₂,
Hence, The intensity of light be maximum is for angles 23.3° and 52.3°.
Based on the sped of the waves and the tension as well as the needed wave speed, the required tension is 13.5 N.
<h3>What is the required tension?</h3>
Given the initial tension and speed, the tension that is required can be found by the formula:
= Initial tension x (Required speed / Initial speed)²
Solving gives:
= 6 x (30 / 20)²
= 6 x 9/4
= 13.5 N
In conclusion, the tension required is 13.5N.
Find out more on the tension on a wire at brainly.com/question/14290894.
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Answer:
şen çal kapimi turkish drama
F1x + F2x = Rx
↓
Rx = F1x + F2x
↓
Rx = F1 cos45° + F2
↓
Rx = (50N)(cos45°) + 60N
↓
Rx = 95N
Similarly, if we sum all the y components, we will get the y component of the resultant force:
F1y + F2y = Ry
↓
Ry = F1y + F2y
↓
Ry = F1 sin45° + 0
↓
Ry = F1 sin45°
↓
Ry = (50N)(sin45°)
↓
Ry = 35N
At this point, we know the x and y components of R, which we can use to find the magnitude and direction of R:
Rx = 95N
Ry = 35N
Answer:
Explanation:
Let the charge on bead A be q nC and the charge on bead B be 28nC - qnC
Force F between them
4.8\times10^{-4} = 
=120 x 10⁻⁸ = 9 x q(28 - q ) x 10⁻⁹
133.33 = 28q - q²
q²- 28q +133.33 = 0
It is a quadratic equation , which has two solution
q_A = 21.91 x 10⁻⁹C or q_B = 6.09 x 10⁻⁹ C
