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Montano1993 [528]
3 years ago
8

Why does a rolling sphere slows down?​

Physics
2 answers:
Lera25 [3.4K]3 years ago
5 0

Friction is resisting gravity and eventually it stops

VLD [36.1K]3 years ago
3 0

The sphere slow down due to friction force between the surface of the sphere and the surface on that the sphere is rolling . The friction force acting against the motion of the sphere. Thats why it is slowed down. In fact not only a sphere, anything can not slow down untill a force act against it's motion.

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A fault in which the hanging wall moves down relative to the footwall is a _____.
LuckyWell [14K]
<span>Normal fault. Normal  (extensional ) fault is a displacement of a rock as a result of rock-mass movement and occurs when the crust is stretching. Because of the stretching the thickness of the crust is reduced and the crust or horizontally extended. </span>



4 0
2 years ago
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Calculate the average force that must be exerted on a 0.145 kg baseball in order to give it an acceleration of 130 m/s^2. (round
r-ruslan [8.4K]

Answer:

18.9 <em>N or </em><em>19</em><em> N </em>rounded

Explanation:

m = 0.145 kg

a = 130 m/s^2

F = ma = (0.145 kg)(130 m/s^2) = 18.9 <em>N</em>

7 0
3 years ago
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so i had to work for halloween, my first Halloween working. When i got home my lil bro showed me all the candy he collected so i
Mrrafil [7]

Answer:

now that's a sweet little bro

4 0
2 years ago
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I would love to stretch a wire from our house to the Shop so I can 'call' my husband in for meals. The wire could be tightened t
dezoksy [38]
Note: I'm not sure what do you mean by "weight 0.05 kg/L". I assume it means the mass per unit of length, so it should be "0.05 kg/m".

Solution:
The fundamental frequency in a standing wave is given by
f= \frac{1}{2L} \sqrt{ \frac{T}{m/L} }
where L is the length of the string, T the tension and m its mass. If  we plug the data of the problem into the equation, we find
f= \frac{1}{2 \cdot 24 m} \sqrt{ \frac{240 N}{0.05 kg/m} }=1.44 Hz

The wavelength of the standing wave is instead twice the length of the string:
\lambda=2 L= 2 \cdot 24 m=48 m

So the speed of the wave is
v=\lambda f = (48 m)(1.44 Hz)=69.1 m/s

And the time the pulse takes to reach the shop is the distance covered divided by the speed:
t= \frac{L}{v}= \frac{24 m}{69.1 m/s}=0.35 s
7 0
3 years ago
If you exert a force of 100.0 N to lift a box a distance of 0.5 m, how much work do you do? 200 J 400 J 50 J 26 J
jeyben [28]
Work = force x distance
= 100N (force) x 0.5m (distance)
=  50J
4 0
3 years ago
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