#1
Jill and Scott both moves for 30 minutes
now if Jill cover 5 km distance and Scott cover 10 km distance
now we know that the formula of speed is given as

now we will have
speed of Jill

speed of Scott

so correct answer here is
<em>Scott had the faster speed since he rode at 20 k/h while Jill only traveled 10 km/h.</em>
<em>#2</em>
distance travelled by each car is given as

now here it is given that
time taken by green car

time taken by yellow car

now we can find the speed of two cars

speed of green car

speed of yellow car

so correct answer will be
<em>The yellow car was faster. Yellow traveled at a speed of 50 mph while green was traveling at an average of 40 mph.</em>
Answer:
There is a force that has the same magnitude as that of the hammer applied on the astronaut and with direction away from the asteroid, movement is given by
F_hammer - F_Gravitation = m a
Explanation:
For this exercise we will propose its solution from Newton's third law, which states that every action has a reaction of equal magnitude, but felt different.
As it is in space, we must assume that it is not subject to the gravitational attraction of nearby bodies, except the asteroid that attracts it. When he extends his hand and hits the asteroid, he exerts a force on him, by Newton's third law he responds with a force of equal magnitude applied to the astronaut, therefore without the two they are not united they could separate if this force is greater than the force of universal attraction between the two.
In summary There is a force that has the same magnitude as that of the hammer applied on the astronaut and with direction away from the asteroid, movement is given by
F_hammer - F_Gravitation = m a
Answer:
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