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Anettt [7]
1 year ago
14

Consider the graph below that represents the variation of the velocity with respect to time of an object moving along the x - ax

is . The distance traveled during the second part of the trip ( 10s to 18s ) is equal to :

Physics
1 answer:
vazorg [7]1 year ago
3 0

In a velocity-time graph, the area under the curve represents the distance.

The distance traveled from 10s to 18 s is

\begin{gathered} d\text{ = }\frac{1}{2}\times10\times(18-10) \\ =\text{ 40 m} \end{gathered}

Final Answer: The distance traveled is 40 m from time 10 s to 18 s.

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Answer:

Yes, it should be.

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4 years ago
HELP PLEASE NOWWWW !!!! ( 1 )   Jill and Scott both road their bikes for 30 minutes.  Jill traveled 5 kilometers and Scott trave
katovenus [111]

#1

Jill and Scott both moves for 30 minutes

now if Jill cover 5 km distance and Scott cover 10 km distance

now we know that the formula of speed is given as

speed = \frac{distance}{time}

now we will have

speed of Jill

v = \frac{5}{0.5} = 10 km/h

speed of Scott

v = \frac{10}{0.5} = 20 km/h

so correct answer here is

<em>Scott had the faster speed since he rode at 20 k/h while Jill only traveled 10 km/h.</em>

<em>#2</em>

distance travelled by each car is given as

d = 400 miles

now here it is given that

time taken by green car

t_1 = 10 hours

time taken by yellow car

t_2 = 8 hours

now we can find the speed of two cars

speed = \frac{distance}{time}

speed of green car

v = \frac{400}{10} = 40 mph

speed of yellow car

v = \frac{400}{8} = 50 mph

so correct answer will be

<em>The yellow car was faster.  Yellow traveled at a speed of 50 mph while green was traveling at an average of 40 mph.</em>

6 0
3 years ago
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Floating in deep space, you find yourself at rest next to a small asteroid. You reach out and tap the asteroid with a hammer. Wh
Andrei [34K]

Answer:

There is a force that has the same magnitude as that of the hammer applied on the astronaut and with direction away from the asteroid, movement is given by

                F_hammer - F_Gravitation = m a

Explanation:

For this exercise we will propose its solution from Newton's third law, which states that every action has a reaction of equal magnitude, but felt different.

As it is in space, we must assume that it is not subject to the gravitational attraction of nearby bodies, except the asteroid that attracts it. When he extends his hand and hits the asteroid, he exerts a force on him, by Newton's third law he responds with a force of equal magnitude applied to the astronaut, therefore without the two they are not united they could separate if this force is greater than the force of universal attraction between the two.

In summary There is a force that has the same magnitude as that of the hammer applied on the astronaut and with direction away from the asteroid, movement is given by

                F_hammer - F_Gravitation = m a

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Answer:

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Explanation:

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