Question

A ball is projected with 40m/s vertically upward. (Ignore air resistance)

Answer 1

Make us of equation of motion formulas.

a.) the total time of flight = 8.16 s

b.) the maximum height reached = 81.6 m

c.) the velocity at t = 5s = 9 m/s

Motion Under Gravity

Motion of any object under gravity is the vertical motion of the object under the influence of acceleration due to gravity.

Given that a ball is projected with 40 m/s vertically upward.

A. the total time of flight of the ball will be T = 2t

At maximum height, v = 0.

v = u - gt

0 = 40 - 9.8t

9.8t = 40

t = 40 / 9.8

t = 4.08 s

T = 2 × 4.08

T = 8.16 s

B. the maximum height H can be found by using the formula

v² = u² - 2gH

At maximum height, v = 0

0 = u² - 2 × 9.8 × H

40² = 19.6H

H = 1600/19.6

H = 81.6 m

C. the velocity at t = 5s will be v

v = u - gt

v = 40 - 9.8 × 5

v = 40 - 49

v = - 9 m/s

That is, 9 m/s in the opposite direction ( coming downward )

Therefore, the total time of flight of the ball is 8.16 s, the maximum height reached is 81.6 m and the velocity at t = 5s is 9 m/s

Learn more about Vertical Motion here: brainly.com/question/27526920

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