A weightlifter lifts a 32 kg barbell a distance of 0.1 m in 0.83 s. How much power is demonstrated by the lift?
2 answers:
To find power, you have to find work first.
Given :
F = 32kg —> 313.6 N
d = 0.1m
Work = Fd
= (313.6)(0.1)
= 31.36
P=W/t
=(31.36)/(0.83)
≈ 38 W
Answer:
Explanation:
Work:
A = m·g·h = 32·9.8·0.1 = 31.36 L
Power:
N = A / t = 31.36 / 0.83 ≈ 38 W
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