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hram777 [196]
1 year ago
15

when is the angular momentum of a system constant? when is the angular momentum of a system constant? when no net external torqu

e acts on the system. when the moment of inertia is constant. when no net external force acts on the system. when the total kinetic energy is constant. when the linear momentum and the energy are constant.
Physics
1 answer:
IRISSAK [1]1 year ago
5 0

when no net external torque acts on the system then the angular momentum of a system becomes constant. In mechanics and physics, a torque is the spinning counterpart to a force.

The rotating counterpart of linear momentum in physics is called angular momentum. Given that the total angular momentum is conserved, or remains constant in a closed system, it is an important physical quantity. Angular momentum is conserved in both its magnitude and direction. Bicycles, motorcycles, frisbees, rifled bullets, and gyroscopes are all useful objects thanks to the conservation of angular momentum.

The torque is the ratio of the force's magnitude to the angle at which its line of action is perpendicular to the axis of rotation. The cross product of the position vector and the torque, a three-dimensional pseudovector, yields the torque for point particles.

learn more about torque here

brainly.com/question/28220969

#SPJ4

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Explanation:

a)

In this situation, we have two resistors connected in series.

The equivalent resistance of resistors in series is equal to the sum of the individual resistances, so in this circuit:

R=R_1+R_2

where

R_1=4\Omega

R_2=1 \Omega

Therefore, the equivalent resistance is

R=4+1=5 \Omega

Now we can use Ohm's Law to find the current flowing through the circuit:

I=\frac{V}{R}

where

V = 8 V is the voltage supplied by the battery

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I=\frac{8}{5}=1.6 A

The two resistors are connected in series, therefore the current flowing through each resistor is the same, 1.6 A.

b)

In this part, a third resistor is added in series to the circuit; so the new equivalent resistance of the circuit is

R=R_1+R_2+R_3

where:

R_1=4\Omega\\R_2=1\Omega\\R_3=1\Omega

Substituting, we find the equivalent resistance:

R=4+1+1=6 \Omega

Now we can find the current through the circuit by using again Ohm's Law:

I=\frac{V}{R}

where

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Substituting,

I=\frac{8}{6}=1.33 A

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3 years ago
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