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hram777 [196]
1 year ago
15

when is the angular momentum of a system constant? when is the angular momentum of a system constant? when no net external torqu

e acts on the system. when the moment of inertia is constant. when no net external force acts on the system. when the total kinetic energy is constant. when the linear momentum and the energy are constant.
Physics
1 answer:
IRISSAK [1]1 year ago
5 0

when no net external torque acts on the system then the angular momentum of a system becomes constant. In mechanics and physics, a torque is the spinning counterpart to a force.

The rotating counterpart of linear momentum in physics is called angular momentum. Given that the total angular momentum is conserved, or remains constant in a closed system, it is an important physical quantity. Angular momentum is conserved in both its magnitude and direction. Bicycles, motorcycles, frisbees, rifled bullets, and gyroscopes are all useful objects thanks to the conservation of angular momentum.

The torque is the ratio of the force's magnitude to the angle at which its line of action is perpendicular to the axis of rotation. The cross product of the position vector and the torque, a three-dimensional pseudovector, yields the torque for point particles.

learn more about torque here

brainly.com/question/28220969

#SPJ4

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A dragster with a mass of 700 kg attains a speed of 120 m/s in the quarter mile. Immediately after passing the timing lights, th
Bumek [7]

Answer:

The time taken is 5.55 seconds

Explanation:

Density, p = 1kg/m³

Mass of vehicle, m = 700kg

Initial speed, u = 120m/s

Area of drag chute, A = 7.5 m²

Drag coefficient, Cd = 1.4

Final velocity, v = 20m/s

time taken to decelerate to 20m/s, t = ?

EF = ma

Since the force taken into consideration is the drag force due to the drag chute,

EF = -Fd = -(pACdv²)/2 = ma

a = dv/dt

So the equation can be written as,

-(pACdv²)/2 = m dv/dt

Taking integral of the left hand side with respect to dt and the right with respect to dv with boundaries of 0 to t and u to v,

(pACd)t/2m = (1/v) - (1/u)

t = (2m/pACd) x ( (1/v) - (1/u) ) = f(V)

At V = v

t = (2 x 700)/(1)(7.5)(1.4) x (1/20) - (1/120)

t = 5.55 seconds

6 0
4 years ago
What is the weight of an with a mass of 32kg
Salsk061 [2.6K]

Answer:

22

Explanation:

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5 0
4 years ago
Calculate the number of vacancies per cubic meter at 1000°C for a metal that has an energy for vacancy formation of 1.22 eV/atom
Daniel [21]

To solve this problem, it is necessary to take into account the concepts of the number of vacations N_v at a given temperature as well as the calculation of the number of atom sites per cubic meter.

For definition the number of atomic sites per cubic meter is given as,

N = \frac{N_A\rho}{A}

Where,

N_A = 6.02210^{23}atoms/mol \rightarrow Avogadro's number

\rho density

A = Atomic weight

Replacing with our values we have

N = \frac{(6.02210^{23}atoms/mol)(6.25g/cm^3)(10^6cm^3/m^3)}{37.4g/mol}

N = 1*10^{29}atoms/m^3

At the same time we know that the number of vacancies N_v is defined as,

[tex]N_v = Ne^{-\frac{Q_v}{KT}}[/tex]

Where,

Q_v = Energy of vacancy

K = 8.62*10^{-5} ev/Atom.K \rightarrow Boltzman constant

T = Temperature

Replacing with the values given we have

N_v = (1*10^{29}atoms/m^3)e^{-\frac{1.22eV/atom}{(8.62*10^{-5}eV/atom.K)(1273K)}}

N_v = 1.49*10^{24}m^{-3}

Therefore the number of vacancies per cubit meter at 1000°C is N_v = 1.49*10^{24}m^{-3}

5 0
4 years ago
The graph shows two runners participating in a race.
Olin [163]

Answer:

'Daniela had a 5-meter head start, and Leonard caught up to her at 25 meters.'

Explanation:

hope that helps :)

6 0
3 years ago
Read 2 more answers
How to understand that an inductor behaves like short circuit and capacitor like an open circuit in steady state in a network?
garik1379 [7]
It depends on the steady-state frequency. At zero frequency an inductor behaves like an open circuit. As the frequency increases, the inductor acts more like an open circuit and a capacitator acts more like a short circuit
8 0
3 years ago
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