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Svetlanka [38]
9 months ago
5

Please help!!!! ⚠️⚠️⚠️⚠️⚠️⚠️⚠️⚠️

Chemistry
1 answer:
Bumek [7]9 months ago
6 0

Polyatomic ions: CH_3COO^-, NO_3^-, NH^+, CN^-, Li^+, and OH^-

Monatomic ions: Ca^{2+, O^{2-, and Fe^{3+

<h3>Monoatomic vs Polyatomic Ions</h3>

In chemistry, monoatomic ions are ions that consist of only a single type of atom. They are usually positive or negatively charged and are otherwise known as simple ions. Examples include  Ca^{2+, O^{2-, and Fe^{3+

Polyatomic ions, on the other hand, are ions that consist of more than one atom, unlike monoatomic ions. The two or more atoms are covalently bonded and the entire structure behaves like a single chemical entity in reactions. Polyatomic ions are otherwise known as molecular ions.

Examples of polyatomic ions are  CH_3COO^-, NO_3^-, NH^+, CN^-, Li^+, and OH^-

Thus, from the diagram:

  • Polyatomic ions: CH_3COO^-, NO_3^-, NH^+, CN^-, Li^+, and OH^-
  • Monatomic ions: Ca^{2+, O^{2-, and Fe^{3+

More on ions can be found here: brainly.com/question/14982375

#SPJ1

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Considering the definition of ideal gas and gas laws, The Ideal Gas Law not apply and gases are considering real under conditions of high pressure low pressure.

<h3>Definition of ideal gas</h3>

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other.

In other words, an ideal gas is defined as one in which all collisions between atoms or molecules are perfectly elastic and in which there are no intermolecular attractive forces, so they do not interact with each other.

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The Ideal Gas Law not apply and gases are considering real under conditions of high pressure low pressure.

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brainly.com/question/4147359?referrer=searchResults

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1 year ago
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Una piedra es lanzada horizontalmente desde la azote de un edificio de 30 metros de altura, con una velocidad de 12 m/s. Hallar
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Answer: La piedra tarda 2.47 segundos en caer al suelo, y cae a 29.64 metros de la base del edificio.

Explanation:

Ok, tenemos 2 sistemas de ecuaciones para este problema.

Primero, el vertical:

La aceleración es la aceleración gravitatoria, entonces:

a = -9.8m/s^2

para la velocidad podemos integrar sobre el tiempo y obtenemos

v = (-9.8m/s^2)*t + v0

donde v0 es la velocidad inicial, pero la velocidad inicial es solo horizontal, entonces v0 = 0.

Para la posición integramos de vuelta:

p = (1/2)*(-9.8m/s^2)*t^2 + p0

donde p0 es la posición inicial, en este caso, 30m

p = (-4.9m/s^2)*t^2 + 30m

la piedra va a llegar al piso cuando la posición vertical sea igual a 0m

p = 0m =  (-4.9m/s^2)*t^2 + 30m

de aca podemos despejar el tiempo que la piedra tarda en llegar al suelo.

t = √(30/4.9) segundos = 2.47 s.

Ahora, las ecuaciones para el movimiento horizontal son:

Aceleración nula, pues no hay ninguna fuerza actuando en la dirección horizontal.

a = 0

para la velocidad, integramos sobre el tiempo:

v = 0*t + v0 = v0

donde v0 es la velocidad inicial, en este caso, es 12m/s

v = 12m/s

para la posición integramos de vuelta:

p = 12m/s*t + p0

en este caso podemos asumir que estamos inicialmente en el punto x = x0, asi que la posición inicial es p0 = x0.

p = 12m/s*t + x0

entonces, si queremos calcular la distancia entre la base del edificio y el punto donde cae la piedra, tenemos que calcular:

D = p(2.47s) - p(0s)

D = 12m/s*2.47s + x0 - (12m/s*0s + x0)

D = 29.64m

La piedra tarda 2.47 segundos en caer al suelo, y cae a 29.64 metros de la base del edificio.

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