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3 years ago

At the instant shown in the diagram, the car's centripetal acceleration is directed

Physics

1 answer:

serg [7]3 years ago

3 0

Answer:

At the instant shown in the diagram, the car's centripetal acceleration is directed is discussed below in detail.

Explanation:

The direction of the centripetal acceleration is in a circular movement is forever towards the middle of the roundabout pathway. In the picture displayed, the East direction is approaching the center. So, the course of the car's centripetal acceleration is (H) toward the east.

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The worked examples of charged-particle motion are relevant to:______. a. a transistor. b. a cathode-ray tube. c. magnetic reson

Burka [1]

Answer:

B. Cathode Ray Tube

Explanation:

In 1897, British physicist J. J. Thomson showed that cathode rays were composed of a negatively charged particle, which was later named the electron.

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3 years ago

8. A steel ball rolls from rest down a ramp with an acceleration of -3 m/s/s. What is its velocity after rolling for 5 s?

HACTEHA [7]

Answer:

C. -15m/s

Explanation:

using formula, v = u + at

where v = final velocity

u = initial velocity = 0

a = acceleration = -3m/s/s

t = time = 5sec

=> v = 0 + -3×5 = -15m/s

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3 years ago

Select the correct answer.

Svetllana [295]

Answer:

Both are electromagnetic waves

Explanation:

Both microwaves and light waves form a part of the electromagnetic spectrum. Electromagnetic waves are produced as a result of oscillating magnetic and electric fields. when arranged in order of frequencies and wavelengths they form the electromagnetic spectrum.

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3 years ago

A comet is traveling through space with speed 3.01 ✕ 104 m/s when it encounters an asteroid that was at rest. The comet and the

Tcecarenko [31]

Answer: $8.493(10)^{-3} m/s$

Explanation:

According to the conservation of linear momentum principle, the initial momentum $p_{i}$ (before the collision) must be equal to the final momentum $p_{f}$ (after the collision):

$p_{i}=p_{f}$ (1)

In addition, the initial momentum is:

$p_{i}=m_{1}V_{1}+m_{2}V_{2}$ (2)

Where:

$m_{1}=1.71(10)^{14} kg$ is the mass of the comet

$m_{2}=6.06(10)^{20} kg$ is the mass of the asteroid

$V_{1}=3.01(10)^{4} m/s$ is the velocity of the comet, which is positive

$V_{2}=0 m/s$ is the velocity of the asteroid, since it is at rest

And the final momentum is:

$p_{f}=(m_{1}+m_{2})V_{f}$ (3)

Where:

$V_{f}$ is the final velocity

Then :

$m_{1}V_{1}+m_{2}V_{2}=(m_{1}+m_{2})V_{f}$ (4)

Isolating $V_{f}$ :

$V_{f}=\frac{m_{1}V_{1}}{m_{1}+m_{2}}$ (5)

$V_{f}=\frac{(1.71(10)^{14} kg)(3.01(10)^{4} m/s)}{1.71(10)^{14} kg+6.06(10)^{20} kg}$

Finally:

$V_{f}=8.493(10)^{-3} m/s$ This is the final velocity, which is also in the positive direction.

8 0

4 years ago

What is the answer I’m stuck on this one it’s a screenshot for the question

Dmitry_Shevchenko [17]

Answer:

deceleration is the opposite of acceleration

Explanation:

We know that acceleration is the increase of speed with respect to time. So deceleration must be represented on the graph as a decrease in speed over time.a

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2 years ago