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3 years ago

5

At the instant shown in the diagram, the car's centripetal acceleration is directed

1 answer:

serg [7]3 years ago

3 0

Answer:

At the instant shown in the diagram, the car's centripetal acceleration is directed is discussed below in detail.

Explanation:

The direction of the centripetal acceleration is in a circular movement is forever towards the middle of the roundabout pathway. In the picture displayed, the East direction is approaching the center. So, the course of the car's centripetal acceleration is (H) toward the east.

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Suppose you have a piston in a cylinder where the gas temperature is 26.0° C and has a volume of 1.75 L. What is the volume of t

blsea [12.9K]

Answer:

1.62 L

Explanation:

Charle's law for ideal gases states that for a gas kept at constant pressure, the ratio between volume and temperature is constant:

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

where in this problem we have

$V_1 = 1.75 L$ is the initial volume of the gas

$T_1 = 26.0^{\circ}+273=299 K$ is the initial temperature of the gas

$V_2$ is the final volume of the gas

$T_2 = 3.0^{\circ}+273=276 K$ is the final temperature

Solving the equation for V2, we find

$V_2 = \frac{V_1}{T_1} T_2 = \frac{1.75 L}{299 K}(276 K)=1.62 L$

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3 years ago

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Alinara [238K]

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3 years ago

How will a current change if the resistance of a circuit remains constant while the voltage across the circuit decreases to half

beks73 [17]

Answer:

1. The current will drop to half of its original value.

Explanation:

The problem can be solved by using Ohm's law:

$V=RI$

where

V is the voltage across the circuit

R is the resistance of the circuit

I is the current

We can rewrite it as

$I=\frac{V}{R}$

In this problem, we have:

- the resistance of the circuit remains the same: R' = R

- the voltage is decreased to half of its original value: $V'=\frac{V}{2}$

So, the new current will be

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so, the current will drop to half of its original value.

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The acceleration of automobiles is often given in terms of the time it takes to go from 0 mi/h to 60 mi/h. One of the fastest st

Rudiy27

Answer:

9.934 m/s²

Explanation:

Given:

Initial speed of the Bugatti Veyron Super Sport = 0 mi/h

Final speed of the Bugatti Veyron Super Sport = 60 mi/h

Now,

1 mi/h = 0.44704 m / s

thus,

60 mi/h = 0.44704 × 60 = 26.8224 m/s

Time = 2.70 m/s

Now,

The acceleration (a) is given as:

$a=\frac{\textup{Change in speed}}{\textup{Time}}$

thus,

$a=\frac{26.8224 - 0 }{2.70}$

or

a = 9.934 m/s²

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