This question requires the use of the equation of motion:
v = u + at [v is final velocity (0), u is initial velocity (24), a is acceleration, t is time (13)]
to calculate the acceleration. This can then be multiplied by the mass of the plane to obtain the net force via:
F = ma (F is force, m is mass, a is acceleration)
First, we calculate the acceleration:
0 = 24 + 13(a)
a = -24/13 m/s^2
The force is then:
F = 90000 * (-24/13)
F = -1.66*10^5 Newtons
The negative sign indicates that the force and acceleration are in the opposite direction as the velocity (since we took velocity to be positive)
It supports 128 primary partitions.
Answer:
29 seconds
Explanation:
First we have a constant speed of 12 m/s and the distance of 240 m, so to find the time we can use the formula:
distance = speed * time
240 = 12 * time1
time1 = 20 seconds
Then, the speed decreases at 2 m/s2 until it reaches 2 m/s. So to find this time, we use this formula:
Final speed = inicial speed + acceleration * time
2 = 12 - 2 * time2
2*time2 = 10
time2 = 5 seconds.
Then, the speed increases from 2 m/s to 22 m/s with an acceleration of 5 m/s2, so we have:
Final speed = inicial speed + acceleration * time
22 = 2 + 5 * time3
5*time3= 20
time3 = 4 seconds
The total time is:
Total time = time1 + time2 + time3 = 20 + 5 + 4 = 29 seconds
Answer:
Y = Stress / Strain = (F / A) / (l / L) where l is the change in length
Since L is doubled and A remains the same one would expect l, the change in length to also double so Y remains the same.
As an example think of hanging a weight from a spring and the same weight from a similar spring of twice the length - one would expect the longer spring to show twice the extension of the shorter spring.
Answer:
a = 0.1067 [m/s²]
Explanation:
In order to solve this problem, we must first draw a free body diagram with the forces acting on it.
a)
In the attached image we can find the free body diagram.
b)
The net force can be found by performing a sum of forces on the X-axis, these forces are seen in the free body diagram.
∑Fx = Fr
where:
Fr = resultant force [N] (units of Newtons)
![F_{r}=275+275-310\\F_{r}=240[N]](https://tex.z-dn.net/?f=F_%7Br%7D%3D275%2B275-310%5C%5CF_%7Br%7D%3D240%5BN%5D)
c)
Acceleration can be found by means of Newton's second law, which tells us that the sum of the forces in a body or the resulting force is equal to the product of mass by acceleration.
∑F = m*a
where:
m = mass = 2250 [kg]
a = acceleration [m/s²]
![240=2250*a\\a=0.1067[m/s^{2} ]](https://tex.z-dn.net/?f=240%3D2250%2Aa%5C%5Ca%3D0.1067%5Bm%2Fs%5E%7B2%7D%20%5D)
