Answer:
Option B. 6.25 J/S
Explanation:
Data obtained from the question include:
t (time) = 2secs
F (force) = 50N
d (distance) = 0.25m
P (power) =?
The power can be obtained by using the formula P = workdone/time.
P = workdone / time
P = (50 x 0.25)/ 2
P = 6.25J/s
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The velocity of the block leaving the spring is determined as 18.26 m/s.
<h3>
Velocity of the block</h3>
The velocity of the block leaving the spring is calculated from the principle of conservation of energy.
K.E = Ux
¹/₂mv² = ¹/₂kx²
v² = kx²/m
v² = (500 x 2²)/6
v² = 333.33
v = √333.33
v = 18.26 m/s
Thus, the velocity of the block leaving the spring is determined as 18.26 m/s.
Learn more about velocity here: brainly.com/question/4931057
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Answer:
Explanation:
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